xml deserialization using XML element/attributes

Question

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Need your help in setting the xml attributes for XML deserialization.

This is my input xml:

XML

<form>
<question id="QnA">
<answer>AnswerforA</answer>
</question>
<question id="QnB">
<answer>AnswerforB</answer>
</question>
<question id="QnC">
<answer>AnswerforC</answer>
</question>
</form>

The ids of each question element tag correspond to a class property and its value is the innertext of the corresponding answer element.

The .cs file will look like

C#

 public class Test
{

   private string qnaAns;
   private string qnbAns;
   private string qncAns;

    public string QnA
    {
    get{ return qnaAns;}
    set{qnaAns = value;}
    }

    public string QnB
    {
    get{ return qnbAns;}
    set{qnbAns = value;}
    }

    public string QnC
    {
    get{ return qncAns;}
    set{qncAns = value;}
    }
}

and I use the following code for deserialization

C#

XmlSerializer ser = new XmlSerializer(typeof(Test));

XmlReader xr = new xmlReader(inputxml);

Test t = ser.Deserialize(xr) as Test;

Please let me know how to set the XML element/attribute for the Test class to achieve this.

Thanks for your time.

Posted 17-Oct-11 5:31am

Member 8004095

Updated 17-Oct-11 5:34am

Not Active

v2

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Ciumac Sergiu · Answer 1 · 2011-10-17T06:02:00

Solution 2

Hi,
In order to deserialize this type of XML you would need composed objects:

C#

[Serializable]
public class Question
{
[XmlAttribute] public string id; //render as Xml Attribute
public string answer; //default rendering as Xml Element
}

[Serializable]
public class Form
{
[System.Xml.Serialization.XmlElementAttribute("question")] 
public Question [] question; 
}

Then try to desirialize:

C#

XmlSerializer ser = new XmlSerializer(typeof(Form));
XmlReader xr = new xmlReader(inputxml);
Form t = ser.Deserialize(xr) as Form;

Hope this helps

Posted 17-Oct-11 6:02am

Ciumac Sergiu

Comments

Member 8004095 17-Oct-11 22:55pm

Hi,

Thanks for your reply. But still I have to iterate through the question to set/get the QnA property.

I changed the line "Question []" to "List<question>"

public string QnA
{
get { return question[question.FindIndex(t=>t.id=="QnA")].answer;}
set { ; }
}

Is it possible to set the properties (QnA, QnB, QnC) directly by specifying the xmlelement/attributes?

Also, is it possible to specify another parameter "section" along with "question" for the question object i.e

The form can also be

<form>
<question id="QnA">
<answer>AnswerforA

<answer>AnswerforB

</form>

Many thanks for your time.

Not Active · Answer 2 · 2011-10-17T05:35:00

Solution 1

A lot can be learned from reading the documentation
XML Serialization in the .NET Framework[^]

Posted 17-Oct-11 5:35am

Not Active