How to initialize arbitrary-sized integer by just writing the number?

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Hi everyone, i'm writing an arbitrary-sized numeric class.
I know that already written classes exist but i just like doing my own.
When the class will be finished i'd like to write

C#

BigInt n=999999999999999999;

or

C#

BigInt n=new BigInt(999999999999999999);

instead of

C#

BigInt n=new BigInt("999999999999999999");

How to do?
Thanks in advance for your help.

Posted 29-Sep-11 12:38pm

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Simon Bang Terkildsen · Accepted Answer · 2011-09-29T12:43:00

Solution 1

It's not possible, unless you write your own C# compiler
Your only option is the string.

Posted 29-Sep-11 12:43pm

Simon Bang Terkildsen

Updated 29-Sep-11 12:44pm

v2

Comments

Mehdi Gholam 30-Sep-11 1:20am

My 5!

Simon Bang Terkildsen 30-Sep-11 2:03am

Thank you, Mehdi :)