How To use Input String as HeX

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Hi All,

i am developing an application in which user will input a hexnumber and an address, application have override hexnumber at that address. One major issue i am facing that since user is giving value from console it is in the form of string, i want to use same value as no convertion is required ie if user gives 0x9A567BFF it will be in the form of string but i want to the same as hex in application. Please help.

Posted 5-Sep-11 20:58pm

vikasdogra

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satya praveen · Answer 1 · 2011-09-05T21:15:00

StringToHexConvert.java

/**
* Convert a String to Hexa decimal form.
*/
import java.io.*;

class StringToHexConvert {

String stringToHex(String str) {
char[] chars = str.toCharArray();
StringBuffer strBuffer = new StringBuffer();
for (int i = 0; i < chars.length; i++) {
strBuffer.append(Integer.toHexString((int) chars[i]));
}
return strBuffer.toString();
}

public static void main(String[] args) throws IOException {
System.out.print("Enter the String : ");
BufferedReader br =new BufferedReader(new InputStreamReader(System.in));
String inputString = br.readLine();
StringToHexConvert obj = new StringToHexConvert();
String hexString = obj.stringToHex(inputString);
System.out.println("String in hexa form : " + hexString);
}
}
Output of the program:

Enter the String: mahendra
String in hexa form: 6d6168656e647261