How to save picture in the database

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Hi,
I am using following code to save my data to database Where does the statement to save a picture in the database fit?

VB

Dim drNewRowMCQsAns As DataRow
        drNewRowMCQsAns = DsResultSaveNow.tblResult.NewRow

        drNewRowMCQsAns.Item("PaperID") = vrPaperIDInitialized
        drNewRowMCQsAns.Item("StudentID") = vrStudentID
        drNewRowMCQsAns.Item("StudentName") = vrStudentName

        DsResultSaveNow.tblResult.Rows.Add(drNewRowMCQsAns)
        taResultSaveNow.Update(DsResultSaveNow.tblResult)

I have image field in the database but how to save an image?
Thanks

Posted 28-Jul-11 4:57am

Furqan Sehgal

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Kschuler · Answer 1 · 2011-07-28T05:10:00

You haven't posted enough information to really help you. The code you posted doesn't really seem to have anything to do with loading a picture into a database...it looks like you are just saving a couple of string or number fields. Try reading some of the CP Articles[^] for help, or post more information.

(Here[^] is another CP Articles search with different keywords that might help)

#realJSOP · Answer 2 · 2011-07-28T05:09:00

Solution 1

Save the image to a MemoryStream object, and pass MemoryStream.GetBuffer() as a parameter to your stored procedure.

Posted 28-Jul-11 5:09am

#realJSOP

Sergey Chepurin · Answer 3 · 2011-07-28T05:43:00

This code sample in C# (will be not difficult to convert in VB.NET) works well to read images from database and bind dataset with a gridview control.
To get image from gridview and save it in file use MemoryStream Object like here:

VB

'Initialize image variable
 Dim newImage As Image
 'Read image data into a memory stream
 Using ms As New MemoryStream(imageData, 0, imageData.Length)
  ms.Write(imageData, 0, imageData.Length)
  'Set image variable value using memory stream.

     newImage = Image.FromStream(ms, True)
  'Store selected image to a local file in current directory:
     newImage.Save(".\picture.jpg", System.Drawing.Imaging.ImageFormat.Jpeg)
 End Using

How to save picture in the database

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