open image as a process

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i want to open image/audio/video from the resource folder of the application
as a separate process

System.Diagnostics.Process.Start(@"WindowsFormsApplication2.Properties.Resources.photo");

please correct the above code and make it workable

Posted 2-Jul-11 6:29am

vishnulalr

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Matt U. · Answer 1 · 2011-07-02T06:58:00

Solution 2

Perhaps this will lead you in the right direction.

http://msdn.microsoft.com/en-us/library/aa287676(v=vs.71).aspx[^]

Posted 2-Jul-11 6:58am

Matt U.

Comments

RaviRanjanKr 2-Jul-11 14:53pm

Nice Link! My 5 :)

Abhinav S · Answer 2 · 2011-07-02T06:31:00

Solution 1

This thread[^] should help you out.

Posted 2-Jul-11 6:31am

Abhinav S

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vishnulalr 2-Jul-11 12:37pm

thanks Abinav but i want to open an image that stored inside the app as a resource file i cant specify the path please concentrate there

Sergey Alexandrovich Kryukov 2-Jul-11 20:39pm

This is a different story! You never ask about it!

It depends where the player is. If it is inside your application, there is no problem -- you can play it through resource URI. If you want to use external player, I'm afraid all you can do is to create a temporary file and safe resource to that file, then use Process.Start to play it.

--SA

Sergey Alexandrovich Kryukov 2-Jul-11 20:40pm

5 for this answer.

OP wants something very different. So, please see my comment to his answer above and my solution.
--SA

vishnulalr 2-Jul-11 21:58pm

thanks you re wright please help me how can i write a resourcr url for image,video file for video here i am using directx audiovideoplayback.dll

RaviRanjanKr · Answer 3 · 2011-07-02T09:03:00

your code is not correct because Start function need filename as a parameter which is not what you are passing so its taking as a invalid parameter.
you can use WindowsFormsApplication2.Properties.Resources.photo to assign value to pictureBox1.Image to display images in image control.
as

pictureBox1.Image = WindowsApplication2.Properties.Resources.photo;

This Link-[How to Use Resource File in C#][^] might help you. for further references.

Sergey Alexandrovich Kryukov · Answer 4 · 2011-07-02T14:34:00

You can actually do it if the file extension of your media file is registered in the system and has some "Open With" application. If usually happens when you install and/or configure appropriate failure.

The different thing is: you cannot use any hard-coded file names. There are no situations where it can be useful. Use, for example, an Open File dialog. I hope you put it in code just with the purpose of asking a question, or experimentally.

[EDIT: answering a follow-up question about a file embedded in resource]
Please see my comment to the solution by Abhinav.

—SA

open image as a process

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