please check the error in this javascript code

Question

3.50/5 (2 votes)

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C#

if (y.charAt(0)!="9"||y.charAt(0)!="8"||y.charAt(0)!="7"||y.charAt(0)!="6")
           {
                alert("it should  with 9 or 8 or 7 or 6");
                theForm.txtPhone.focus();
                return false
           }

i am writing this code for validating phone number
but is working only for number start with 9 only.

i think my or operation is wrong .

my full code is

C#

var y = theForm.txtPhone.value;
       if (theForm.txtPhone.value == "")
       {
       alert("Enter phone number");
              theForm.txtPhone.focus();
              return false;
       }
       if(isNaN(y)||y.indexOf(" ")!=-1)
           {
              alert("Enter numeric value");
              theForm.txtPhone.focus();
              return false;
           }
           if (y.length != 10)
           {
                alert("enter 10 characters");
                theForm.txtPhone.focus();
                return false;
           }
           if (y.charAt(0)!="9"||y.charAt(0)!="8"||y.charAt(0)!="7"||y.charAt(0)!="6")
           {
                alert("it should  with 9 or 8 or 7 or 6");
                theForm.txtPhone.focus();
                return false
           }

please help me

vara prasad

Posted 22-May-11 23:31pm

PRASAD GDV

Updated 22-May-11 23:35pm

v3

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3 solutions

Solution 3

in this case you need to check with "And" condition instead of "OR"
if you want to use "OR" then you need to check the opposite condition like below

if (y.charAt(0)=="0"||y.charAt(0)!="1"||y.charAt(0)!="2"||y.charAt(0)!="3"||y.charAt(0)!="4"||y.charAt(0)!="5")

Posted 23-May-11 1:41am

skantg

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Prerak Patel · Accepted Answer · 2011-05-22T23:35:00

Solution 1

Use && instead

if (y.charAt(0)!="9" && y.charAt(0)!="8" && y.charAt(0)!="7" && y.charAt(0)!="6")

Posted 22-May-11 23:35pm

Prerak Patel

v2

Comments

PRASAD GDV 23-May-11 5:48am

thank you very much it is working

Prerak Patel 23-May-11 5:54am

You are welcome.

PRASAD GDV 23-May-11 5:50am

but how it is possible as we are checking for 'or' condition

Prerak Patel 23-May-11 5:53am

You can check in 2 ways,
1. Number starts with this or this or this
2. Number doesn't start with this and this and this

So, you can use
1. == with ||
2. != with &&

PRASAD GDV 23-May-11 5:52am

ok i know the reson

RakeshMeena · Accepted Answer · 2011-05-22T23:42:00

Solution 2

Please check the logic again, I believe you should use the "AND" operator instead of "OR".

OR

Use "==" instead of "!=" if you want to keep "OR" operator.

Posted 22-May-11 23:42pm

RakeshMeena

Comments

PRASAD GDV 23-May-11 5:52am

yes you r correct