not getting value of FileUpLoad after postback

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hi all,

i have FileUpLoad Control and Button control (UpLoadButton).I've facing problem like though FileUpLoad containg file path,it is showing null once after postBack or UpLoadButton clicked.

i've used following code:

protected void btn_UpLoadButton_Click(object sender, EventArgs e)
{

  if (FileUpload1.PostedFile.FileName!= null)//here is my doubt that showing Null Value though it's filled
  {
     HttpPostedFile File1 = FileUpload1.PostedFile;
     Data = new byte[File1.ContentLength];
     File1.InputStream.Read(Data, 0, File1.ContentLength);
     //  Session["ScannedPhotoData"] = Data;

     string strFilename = getFilename(FileUpload1.PostedFile.FileName);
     string strFilepath = "ImageFolder\\" + strFilename;
     string Photo = Server.MapPath(strFilepath);
     //if (File.Exists(Photo))
     //    File.Delete(Photo);
     FileUpload1.PostedFile.SaveAs(Photo);
     ImgScannedPhoto.ImageUrl = "imageview.aspx?img=" + Photo;
     //ScannedPhotoPath.Text = Photo;
  }
}

please reply thanks

Posted 22-Apr-11 2:34am

ks ravi

Updated 22-Apr-11 2:53am

Marc A. Brown

v2

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jayantbramhankar 23-Apr-11 2:36am

Are you using UpdatePanel on this Page?

3 solutions

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demouser743 · Answer 1 · 2011-04-22T02:57:00

Solution 1

You can't retain value in FileUpload control. This is because of security reasons. you can use RequiredFieldValidator for keyname textbox.

Posted 22-Apr-11 2:57am

demouser743

Updated 22-Apr-11 3:09am

v3

Anupama Roy · Answer 2 · 2011-04-22T06:20:00

Solution 2

Try saving the value to a session variable or a hidden field to preserve the data.Have a look at this article.

http://www.ironspeed.com/articles/Maintain%20File%20Upload%20Control/Article.aspx[^]

Posted 22-Apr-11 6:20am

Anupama Roy

Prasanta_Prince · Answer 3 · 2011-04-22T19:50:00

if (Fup1.HasFile)
{
    string FilePath = "";
    string[] a = new string[1];
    string fileName = "";
    string FullName = "";
    try
    {
        if (Fup1.FileName.Length &gt; 0)
        {
            a = Fup1.FileName.Split('.');
            fileName = Convert.ToString(System.DateTime.Now.Ticks) + "." + a.GetValue(1).ToString();
            FilePath = Server.MapPath(@"~\FolderName");
            Fup1.SaveAs(FilePath + @"\" + fileName);

            FullName = FilePath + @"\" + fileName;
            // Database Save Operation of filename.

        }
    }
    catch
    {
    }
}

You can try with this.
If with this error is not solved then try,-

FileUploader.Atribute.add("Value",FileUploader.PostedFile);

In PageLoad.

Hope this can help you.