how can i find the number of words in this program ?

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// helpword.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include <string>

using namespace std;



int main () 
{
	
	int space = 0 ;
  string myString = "" ; 
  int i = 0 , p ;
	cout << "enter a sentence :"  << endl ;
	getline( cin , myString ) ;	
	cout << myString.length() << endl ;
	
	   

	//for(int i = 0; i < myString.length(); i++){
	//	if(myString.at(i) ==  ' ' )
	//	{
	//		h++;
	//	}
	//}cout<<"words"<<h<<endl;
	//  while((myString)  != '*'  )
 // {
 //   character ++;
 //   if(ch == ' ')
	//word ++;
 // }

 //
 // cout<< "the characters are :" << character + 1  << endl ;
 // cout<< "the words are :" << word+1 << endl ;

	while( i < myString.length() )
	{
	p = i ;
	while( p < 10 + i )
	{
		cout << myString.at(p) ;
		p++ ;
	}
		i += 10 ;
		cout << "\n" ;
	}
	while(myString == ' ')
	{
		space++;
	}
	cout <<"word"<<space + 1 <<endl ;
	
    return 0;
}


</string></iostream>

I cannot work with string

Posted 4-Apr-11 6:13am

yay hello

Updated 4-Apr-11 10:40am

Dalek Dave

v3

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Comments

ZeeroC00l 4-Apr-11 13:12pm

What are you trying to do with this code ? Can you be more specific with the question ?

yay hello 4-Apr-11 13:49pm

i want the numbers of words in a sentence

Аslam Iqbal 4-Apr-11 14:13pm

Are trying to find, how many words in myString variable? Or how many words of your source code file?

ZeeroC00l 4-Apr-11 14:23pm

Ok, if so then why would you increase your counter by 10 every time ?

Dalek Dave 4-Apr-11 16:40pm

Edited for Grammar.

3 solutions

Solution 3

Using The Standard C++ Library can significantly simplify your task.
I will assume that the words are white space separated, here is a demo application with
two different implementations of WordCount, both using the standard library utilities:

C++

#include <iostream>
#include <sstream>
#include <string>
#include <iterator>

// First alternative
int WordCount1(const std::string& str)
{
    int count = 0;
    std::istringstream iss(str);
    for(std::string word; iss >> word; ++count);
    return count;
}

// Second alternative
int WordCount2(const std::string& str)
{
    std::istringstream iss(str);
    return std::distance(std::istream_iterator<std::string>(iss),
                         std::istream_iterator<std::string>());
}

// Lets make a test
int main()
{
    // The test string - note that it contains '\t' and '\n'
    std::string str = "This\tis a test!\nI repeat, this is a test!";
    
    // Show the results:
    std::cout << "\nWordCount1: " << WordCount1(str) << " words"
              << "\nWordCount2: " << WordCount2(str) << " words";
    
    return 0;
}

The program output is:
WordCount1: 10 words
WordCount2: 10 words

You can see the simplicity here... Especially in second alternative which is just 2 lines of code.
Also note that tab ('\t') and new line ('\n') characters are also correctly interpreted.

If you want to understand how these algorithms work check out the documentation for std::istream::operator>>[^] and std::distance[^].

If the documentation is not clear enough for you, you are always welcome to share your concerns here. :)

Best Regards,
Nuri

Posted 4-Apr-11 23:02pm

Nuri Ismail

Solution 1

If you use one of the standard typing definitions where a word is 5 characters then you just need to count the number of characters then divide by 5.
For example you could write:

FileInfo yourFile = new FileInfo(pathName);
int numberOfWords = yourFile.Length/5;

Where pathName is the path to and name of your file. This will allow you to find the number of words in your program as you asked.

Posted 4-Apr-11 7:09am

BillW33

Updated 4-Apr-11 9:07am

v3

Comments

yay hello 4-Apr-11 13:50pm

how ?

BillW33 4-Apr-11 14:27pm

I modified my answer to respond to your question.

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*ZeeroC00l* · Accepted Answer · 2011-04-04T08:31:00

C#

int get_word_count(char *stringInput)
{
  int count = 0;
  char *s;

  while(IS_PUNC(*stringInput))
    stringInput++;
  s = stringInput;

  while(*stringInput)
  {
    while(*s && !IS_PUNC(*s))
      s++;
    if(stringInput - s)
      count++;
    while(IS_PUNC(*s))
      s++;
    stringInput = s;
  }

  return count;
}

This will get you the count of the words in a sentence.

Or otherwise there is another easy way to do it. That is to use the strtok functionality provided by the C++ string.h header.

char * strtok ( char * str, const char * delimiters );

Above is the syntax of how to use the strtok functionality.

strtok[^]

Take a look at the code example. YOu must be able to solve your problem after looking into that