How to convert exponentioal values to double in VC++?

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"3.1e-05" this is the string and I want to convert this string into numeric output ll be 1.00003

Any suggestion will be greatly appreciated.

Posted 29-Mar-11 5:05am

shrikant003

Updated 29-Mar-11 5:57am

Sandeep Mewara

v2

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3 solutions

Solution 1

What's wrong with using sscanf?

Cheers!

Posted 29-Mar-11 5:10am

Manfred Rudolf Bihy

Comments

Sergey Alexandrovich Kryukov 29-Mar-11 12:31pm

I guess, nothing's wrong... with my vote of 5.
--SA

Manfred Rudolf Bihy 29-Mar-11 14:09pm

Thanks SA!

Solution 3

C#

int _tmain(int argc, _TCHAR* argv[])
{
  TCHAR*  e;
  _tprintf(__T("%.5lf"),_tcstod(1<argc?argv[1]:__T("3.1e-05"),&e));
  _gettch();
  return 0;
}

Thats easy, isnt?

Posted 29-Mar-11 6:45am

mbue

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Sergey Alexandrovich Kryukov · Accepted Answer · 2011-03-29T05:15:00

Solution 2

Is it a string or char*? Assuming the latter,

C++

#include <stdlib.h>
const char* str = "3.1e-05";
//...
double value = atof(str);

—SA

Posted 29-Mar-11 5:15am

Sergey Alexandrovich Kryukov

Updated 29-Mar-11 8:09am

v3

Comments

Olivier Levrey 29-Mar-11 12:29pm

My 5. I just fixed the tags...

Sergey Alexandrovich Kryukov 29-Mar-11 12:31pm

Thank you for the fix and the vote.
--SA

Manfred Rudolf Bihy 29-Mar-11 14:09pm

How could I forget the float pendant to atoi. My 5!

Sergey Alexandrovich Kryukov 29-Mar-11 15:06pm

Thank you, Manfred.
--SA