Sql Query for seleting the remaining part..

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i have two tables [friend] and [login]
1. [login] table has all users Id ex:
uid fname
1 A
2 B
3 C
4 D
5 E
2. and [friend] table has 2 columns
[uid][fid]
1 2
1 3
2 4
2 5

Now My problem is that : When i open uid=1 account i need to show taht 4 and 5 are not friends of 1.
Simillarly when i open uid=2 account i want to show 1 and 3 are not friends of 2.

"Need help: Dont now how to apply sql query in this problem".
i have tried "Select fid from friend where uid="+ Session["UID"]; but it is only selecting the fid. now i have to select uid from login table which are not mentioned in fid selected previously.<.

Posted 27-Mar-11 9:30am

naveen.0nick

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Sandeep Mewara 28-Mar-11 13:36pm

Good to know that the question is resolved now.

3 solutions

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Sandeep Mewara · Answer 1 · 2011-03-27T09:36:00

Solution 1

Try:

SQL

SELECT 
   uid, fname
FROM 
   login
WHERE
   uid NOT IN (SELECT fid FROM friend WHERE uid = @uid)
AND
   uid <> @uid

'@uid = value stored in Session["uid"]

Posted 27-Mar-11 9:36am

Sandeep Mewara

Updated 27-Mar-11 9:37am

v2

Comments

Wendelius 27-Mar-11 16:45pm

OP's comment:
Hello Sandeep Mewara
ur code is simple and ok. So i am applying ur code in my project. thanx eveyone for giving ur time.

Sandeep Mewara 28-Mar-11 10:54am

Good to know that it has resolved your issue.

Perry Bruins · Answer 2 · 2011-03-27T09:39:00

Solution 2

Hi naveen.0nick,

Try below query:

select login.uid, login.fname
from login
where login.uid <> Session["UID"]
and login.uid not in
(
select friend.fid
from friend
where friend.uid = Session["UID"]
)

Regards, perry

Posted 27-Mar-11 9:39am

Perry Bruins

Comments

Wendelius 27-Mar-11 16:44pm

From OP's solution:

Hi Perry
Salute boss!!!

i have got my answer.
thanx man.

Now i am trying other queries suggested by Costica and Sandeep also.
Thanx every1 for helping me out

Costica U · Answer 3 · 2011-03-27T09:42:00

Solution 3

If I understood ( your question is not too clear) correctly, try this

SQL

select  lg.uid,
        lg.fname,
        fr.fid
from   [login]  lg
join   [friend] fr
       on fr.uid<>lg.uid
where  lg.uid = @uid

Posted 27-Mar-11 9:42am

Costica U