How to write a linqdatasource _inserting (object sender,linqDatasourceInsertEvent args)?

Question

4.00/5 (2 votes)

See more:

How to write a linqdatasource _inserting (object sender,linqDatasourceInsertEvent args)?

I use a detail view (select from masterview already), but when i write back to sql i will take either a session[userid] or master gridview1.[userId] selected value.

Or just simply ask for Inserting function for Linqdatasoure with LinquDataSourceInsertEvent?

Posted 14-Mar-11 13:11pm

Member 7751939

Updated 14-Mar-11 14:04pm

Yusuf

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Piccadilly Yum Yum · Answer 1 · 2011-03-16T04:30:00

I found that on msdn, maybe help ?

C#

protected void LinqDataSource_Inserting(object sender, LinqDataSourceInsertEventArgs e)
{
    Product product = (Product)e.NewObject;
    product.DateModified = DateTime.Now;
}

XML

protected void LinqDataSource_Inserting(object sender,
        LinqDataSourceInsertEventArgs e)
{
    if (e.Exception != null)
    {
        foreach (KeyValuePair<string, Exception> innerException in
             e.Exception.InnerExceptions)
        {
        Label1.Text += innerException.Key + ": " +
            innerException.Value.Message + "<br />";
        }
        e.ExceptionHandled = true;
    }
}