Input button inside a table calling javascript

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Hello,

I have an input button inside a form, inside a table, in a row, in a cell.
It doesn't work.

I put the same button outside of thee table no problem.

Do I have to set something on the table?

Thanks,

-ren

<input type="button" value="Button" name="B3" onclick="alert('hello');"></td>

Posted 12-Mar-11 23:38pm

renasis_

Updated 13-Mar-11 2:41am

Dalek Dave

v6

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Dalek Dave 13-Mar-11 8:41am

Edited for readability.

3 solutions

Solution 3

Hello,

Thanks for the responses. It was improper formatting of the table, one of the rows was messed up.

-ren

Posted 13-Mar-11 10:17am

renasis_

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Sandeep Mewara · Accepted Answer · 2011-03-13T01:25:00

Nothing looks wrong nor anything extra is needed.

<input type="button" value="Button" name="B3" onclick="alert('hello');">

inside or outside a table should work and Javascript alert should be triggered.

Look in the designer if the table is correctly formed. Try to view-source the page with button in table and see if all looks good. If you are unable to, then post the viewsource (not all just the table part) for us to see.

Yusuf · Accepted Answer · 2011-03-13T01:39:00

Solution 2

Many times there many be something that is preventing the the javascript code from executing. Well, take a look behind the scene, by utilizing the handy danady debugger. Unfortunately there is no simple or single way of debugging javascpit. Each browser has 'their' way of hooking into it. Some easy and straight forward while other, well let us leave it there.

Check FireFox's FireBug[^], Chrome's Script Debugger[^] Or IE's [don't want to go that far I hope]

You may be able to find out what it is not been called or executed.

Posted 13-Mar-11 1:39am

Yusuf

Comments

Dalek Dave 13-Mar-11 8:42am

Sage advice.

Espen Harlinn 13-Mar-11 9:05am

It's pretty hard to debug onclick="alert('hello');" - eyeballing the html is probably what OP needs to do ... knowing how to do it is still a good thing, so my 5

Yusuf 13-Mar-11 10:15am

I totally agree.
What I struggle many times in this forum is that, the question is not clear and well defined. So, just giving simple pointer or advice does not make justice in the face of the question.

I was tempting to elaborate more, but where do you draw the line between writing tip/trick, article or simple advice. In reality in order my advice to be meaningful, the alert() needs to be replaced with simple javascript function call and the alert() placed inside the function. That way true debugging can take place.

Espen Harlinn 13-Mar-11 10:19am

I know - and I know *you* know, as can be easily discerned from your efforts here in the Q&A section :)

Yusuf 13-Mar-11 11:16am

Thanks