Display XML Conten in a label

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How can i display an xml content in a label the following is the xml content

<?xml version="1.0" encoding="utf-8" ?>
<Books>
    <Text>
       <Subject>
           Alpha
       </Subject>
       <Content>
           Bravo
       </Content>
    </Text>
<Books>

I want to display the content as

Subject:Alpha
Content:Bravo

in two different labels

Posted 13-Jan-11 22:30pm

MathewPV

Updated 13-Jan-11 22:34pm

v2

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Anupama Roy · Answer 1 · 2011-01-13T23:30:00

Solution 4

Write a LINQ similar to this & try

C#

// Create the query
            var books = from c in System.Xml.Linq.XElement.Load("Books.xml").Elements("Text")
                        select c;
            if (books != null)
            {
                foreach (var b in books)
                {

                    string subjectvalue = b.Element("Subject").Value; //will give you Alpha
                }
            }

Posted 13-Jan-11 23:30pm

Anupama Roy

Comments

Espen Harlinn 14-Jan-11 9:20am

5+ Yes, that's an easy workable solution

Anupama Roy 16-Jan-11 4:29am

Thanks Espen.

Brij · Answer 2 · 2011-01-13T22:36:00

Solution 1

So what problem you are facing, You need to parse the XML and access the appropriate nodes and assign it to Label's text property.

You can query to your XML using XPath. Have a look to the link for example

Posted 13-Jan-11 22:36pm

Brij

CPallini · Answer 3 · 2011-01-14T00:58:00

You may use something like

XmlDocument xmldoc = new XmlDocument();
xmldoc.Load("mydata.xml");
label1.Text = xmldoc.SelectSingleNode("/Books/Text/Subject").FirstChild.Value;
label2.Text = xmldoc.SelectSingleNode("/Books/Text/Content").FirstChild.Value;

Provided you correctly fix your XML document (the bottom node should be </Books>)

Espen Harlinn · Answer 4 · 2011-01-13T22:40:00

Solution 2

Create an xml schema for your xml file and use xsd.exe[^] to generate code for the schema.

Use generated code to deserialize[^] contents of xml file. At this point you have a collection representing you data in memory.

Use the Data Repeater[^] to create your ui.

Regards
Espen Harlinn

Posted 13-Jan-11 22:40pm

Espen Harlinn

Updated 13-Jan-11 22:43pm

v2

Estys · Answer 5 · 2011-01-13T23:09:00

Solution 3

In addition to the excellent answers already given, you could look into xsl transformations :
http://www.w3schools.com/xsl/[^]

Cheers

Posted 13-Jan-11 23:09pm

Estys