How do I form this regex?

Question

2.50/5 (2 votes)

See more:

I don't know much about regex and no-one here is sober enough to help.

I have to search a string:
"ghlkj djfghdf word99999x dfkl;klsdf sdgjkhdfgjk fdsdsfsd"
and find "word99999x"

word - will be a variable length alpha string.
99999 - a five digit number.
x - one of a list of characters - e.g. xyz

Any help how to form this would be much appreciated.

Posted 23-Dec-10 1:08am

Nagy Vilmos

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2010-12-23T01:22:00

Solution 1

Try

([a-zA-z]+\d{5}[xyz])

Have a look at Expresso[^] - it's free and really helps with regexes!

Posted 23-Dec-10 1:22am

OriginalGriff

Comments

sjelen 23-Dec-10 8:39am

You have a typo: 'A-z' instead 'A-Z'.
I would add marking of first and last char in word (\b):
(\b[a-zA-Z]+\d{5}[xyz]\b)

Nagy Vilmos 23-Dec-10 8:40am

Thanks Griff.

Manfred Rudolf Bihy 23-Dec-10 10:07am

Good call! +5
Good link +5 ... Oh wait, I ran out of voting options :)