Why is their a "=0" at the end of the method declaration?

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why is their a "=0" at the end of the method declaration?

class GamePiece { public: virtual std::unique_ptr<gamepiece> clone() const= 0; };

What I have tried:

why is their a "=0" at the end of the method declaration?

class GamePiece { public: virtual std::unique_ptr<gamepiece> clone() const= 0; };

Posted 17-Dec-18 13:00pm

Member 13010616

Updated 17-Dec-18 23:11pm

v3

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Patrice T 17-Dec-18 19:05pm

there is no 'a =0' in this code !

[no name] 17-Dec-18 19:15pm

It says. class GamePiece { public: virtual std::unique_ptr<gamepiece> clone() const= 0; };

CPallini 18-Dec-18 3:19am

Could you please post the whole code here?
(Modify the original post).

Richard MacCutchan 18-Dec-18 5:12am

Same help vampire as yesterday.

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Peter Leow · Answer 1 · 2018-12-17T16:23:00

Solution 1

It is a pure virtual function. A class is abstract if it has at least one pure virtual function. A pure virtual function is declared by assigning 0 in declaration. Read more Pure Virtual Functions and Abstract Classes in C++[^]

Posted 17-Dec-18 16:23pm

Peter Leow

Updated 17-Dec-18 16:24pm

v2

Richard MacCutchan · Answer 2 · 2018-12-17T23:12:00

Solution 2

I told you the answer yesterday, and suggested (yet again) that you stop wasting your time posting questions here and actually studied the C++ language.

Posted 17-Dec-18 23:12pm

Richard MacCutchan

v2