C++ dynamic array problem?

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C++14

/* A function that reads a sequence of integers from input (with the length of sequence, followed b
For example, if the length is 3, and the numbers are
123 345 99 then the array returned will be of size 3, and stores values 123, 345, and 99
@param length: upon return, stores the length/size of the array
@return the pointer pointing to the array
*/

int * ReadNumberSequence (int & size)
{
int * array = NULL; // initialize the pointer to NULL
do {
cout <<"Enter the length of the number sequence:";
cin >> size;
} while (size<=0);

// Todo: Write a statement to allocate memory for the array.
// Note: we only know the value of size at run time, so we need to DYNAMICALLY
// allocate memory for this array

// Todo: write a loop to read size # of int from input, and save them to the //array

array = new int [size];

for (int i = 0; i < size; i++)
{
cin >> array[i];
}

return array;
}

int main()
{
// i'm not sure what to do here
// Todo: delcare necesssary variables

//Todo: call the ReadNumberSequence function to read a sequence of numbers


//Todo: write a loop to


display the elements in the array returned ...
//Todo: free the array returned by ReadNumberSequence.

}

What I have tried:

I have completed the dynamic array fuction called int * ReadNumberSequence, but I'm stuck and don't know what to write in the main function.