Define an index in ruby equal to nil and return false

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I am trying to define a method that checks if a given space on the board is empty and address the scenarios that qualify as an empty space that isn't equal to the literal " ".

My tests failed to produce false/true, and instead provided nil.

What I have tried:

board = [" ", " ", " ", " ", " ", " ", " ", " ", " "]
def position_taken?(board, index)
if board[index] == [" "] || nil
puts false
elsif board[index] != [" "]
puts true
end
end
end

Posted 1-Sep-18 6:44am

Member 13969616

Updated 2-Sep-18 4:39am

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Patrice T · Answer 1 · 2018-09-01T07:41:00

Quote:
My tests failed to produce false/true, and instead provided nil.

The reason is that your code do not cover all cases.
Try something like this:

VB

board = [" ", " ", " ", " ", " ", " ", " ", " ", " "]
def position_taken?(board, index)
    if board[index] == [" "] || nil # not sure what this is supposed to be
        puts false
    elsif board[index] != [" "]
        puts true
    else
        # put a warning message here and you will have surprise
    end
end
end

The reason is that board[index] == [" "] || nil and board[index] != [" "] are not complementary conditions.
In case second condition should be complement of first, the code should be simply:

VB

board = [" ", " ", " ", " ", " ", " ", " ", " ", " "]
def position_taken?(board, index)
    if board[index] == [" "] || nil
        puts false
    elsif board[index] != [" "]
    else
        puts true
    end
end
end

Nota: I have never used Ruby, I just know common usages in other languages.

Member 13969616 · Answer 2 · 2018-09-02T04:39:00

def position_taken?(board, index)
if board[index] == " " || board[index] == nil || board[index] == ""
return false
elsif board[index] != " "
return true
end
end

Thank you for your help, I ended up finding this solution worked and what the problem was by seeing how you interpreted my code.

Define an index in ruby equal to nil and return false

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