How to compare the two tables in mysql using the PHP code?

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Hi,

I have two tables and I have to compare the tables data and if data matches that assign the value "Yes" to the column status and if unmatched then assign the value "No" to that status column and i have to do this for multiple values. I need to do this using PHP and display the data in PHP table with the matched value status and unmatched value status.

Thanks in advance.

What I have tried:

I have tried sql query and able to fetch the unmatched values in table but not able to assign the status to matched and unmatched values.

Posted 9-May-18 5:29am

Member 13819325

Updated 16-Apr-21 3:20am

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W∴ Balboos, *GHB* · Answer 1 · 2018-05-09T08:14:00

Solution 1

I think you'll find MySQL: INTERSECT Operator[^] most helpful.

Run each table UPDATE against the other table to set 'Yes' and 'No' with simple "IN" and "NOT IN".

Posted 9-May-18 8:14am

W∴ Balboos, GHB

Member 13117853 · Answer 2 · 2019-06-27T22:44:00

Solution 3

You can write a query like this one:

$sql = "UPDATE table1 t1
JOIN table2 t2
ON t2.id = t1.id

SET t1.status = "YES" ";

This should work well

Posted 27-Jun-19 22:44pm

Member 13117853

Comments

CHill60 28-Jun-19 5:23am

It will work well for the update but does not satisfy the requirement "display the data in PHP table with the matched value status and unmatched value status"

Member 13819325 · Answer 3 · 2018-05-09T20:29:00

Solution 2

Can you please help me out with the proper query? I need to apply 'Yes' or 'No' against each of the values in the php table.

Posted 9-May-18 20:29pm

Member 13819325

Comments

Richard Deeming 10-May-18 12:49pm

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