How to store diffrent values in a single variable using loop.

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i am trying to code a program but there is a problem in this code,the problem of storing and remembering 2(may be more) values in a single variable using for loop.
e.g-

C++

int a,i;
 for(i=0;i<2;i++){
   scanf("%d",&a);
 }
 for(i=0;i<2;i++){
    printf("%d ",a);
}

let we enter 3 5 using scanf but it prints 5 5.
but i want 3 5 how to do that. where is the problem.

What I have tried:

In this program variable a,should prints the entered values 3 5,but it returns both 5 5,how does it remember it when printing,print 3 first then print 5.

Posted 13-Mar-18 21:31pm

Member 13725222

Updated 20-Mar-18 8:48am

KarstenK

v2

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Jochen Arndt · Answer 1 · 2018-03-13T21:42:00

Solution 1

You have to use multiple variables or - if they are of same type - an array:

C++

#define MY_ARRAY_SIZE 2

int a[MY_ARRAY_SIZE];
for (i = 0; i < MY_ARRAY_SIZE; i++) {
    scanf("%d", &a[i]);
}
for (i = 0; i < MY_ARRAY_SIZE; i++) {
    printf("%d ", a[i]);
}

Posted 13-Mar-18 21:42pm

Jochen Arndt

Patrice T · Answer 2 · 2018-03-13T22:57:00

Solution 2

Either you merge the 2 loops:

C++

int a,i;
for(i=0;i<2;i++){
    scanf("%d",&a);
    printf("%d ",a);
}

Either you learn about arrays
Arrays in C[^]
C Arrays: Declare, Initialize and Access Elements (With Examples)[^]

Posted 13-Mar-18 22:57pm

Patrice T

Doug Joseph · Answer 3 · 2018-03-20T08:49:00

Well, you could use a character array like this:

Kind of an end-around, but it would work.

int  a, i;
char inval[20], intxt[1000];

intxt[0] = 0; // <== NULL termination of string
for( i = 0; i < 2 ; i++ )
{
    inval[0] = 0; // <== Null terminate input just for safety
    printf( "Enter Item #%0d:", i ); 
    gets( inval );
    strcat( intxt, "=" );  // <== some token ('=')
    strcat( intxt, inval ); 
}

i = 0;
do
{
    if ( intxt[i] != 0 )
    {
        if ( intxt[i] == '=' )
        {
            sscanf( &intxt[i+1], "%d", &a ); 
            printf( "%d ", a );
        };
    };    
    
} while ( ( intxt[i] != 0 ) && ( i < 1000 ) );

printf( "\n" );

-Doug