what a great than datatype long

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static void Main(string[] args)
{
  long    virus ;
           
  virus = Convert.ToInt32(Console.ReadLine ());
  string c="";
  for (int x = 0; x<=120; x++)
  {
    //   Console.WriteLine(b.ToString ()); 
    virus = virus * 2;
    //c = b.ToString();
  }
  Console.WriteLine((virus).ToString ());
  Console.Read();
}

why give me zero?

Posted 29-Oct-10 20:47pm

Mostafa Elsadany

Updated 29-Oct-10 20:49pm

JF2015

v2

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5 solutions

Solution 5

static void Main(string[] args)
{
double virus;
virus = Convert.ToInt32(Console.ReadLine());
for (int x = 0; x <= 120; x++)
{
// Console.WriteLine(b.ToString ());
virus = virus * 2;
//c = b.ToString();
}
Console.WriteLine(virus);
Console.Read();
}

It is giving solution in exponential form.

Posted 29-Oct-10 21:39pm

Mohd Wasif

Solution 6

What exactly do you want with it?
Creating a 128bit (or bigger) may do the trick if you want integers. It'll be faster than a BigNum, and it won't suffer from the accuracy problem of a double.

Posted 30-Oct-10 8:28am

harold aptroot

Comments

Mostafa Elsadany 2-Nov-10 20:27pm

static void Main(string[] args)
{
long virus ;

virus = Convert.ToInt32(Console.ReadLine ());
string c="";
for (int x = 0; x<=120; x++)
{
// Console.WriteLine(b.ToString ());
virus = virus * 2;
//c = b.ToString();
}
Console.WriteLine((virus).ToString ());
Console.Read();
}

when try this code give me error because the result is very large
thnx for help

[no name] 3-Nov-10 4:12am

yes.. that's because you actually Didn't do what I suggested, you just used a 64bit data type again.

Solution 3

static void Main(string[] args)
{
long virus;
virus = Convert.ToInt32(Console.ReadLine());
string c = "";
for (int x = 0; x <= 120; x++)
{
// Console.WriteLine(b.ToString ());
virus = virus * 2;

//c = b.ToString();
}
Console.WriteLine(virus);
Console.Read();
}
in this case giving zero
plz try
thnx for help

Posted 29-Oct-10 21:05pm

Mostafa Elsadany

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shakil0304003 · Accepted Answer · 2010-10-29T21:03:00

you can use double, there is no other data type that is integer & gather than long. I think you multiply the value by 2^120. It will be out of range in long. You also can use string for integer multiplication.

static void Main(string[] args)
{
  double    virus ;
           
  virus = Convert.double(Console.ReadLine ());
  string c="";
  for (int x = 0; x<=120; x++)
  {
    //   Console.WriteLine(b.ToString ()); 
    virus = virus * 2;
    //c = b.ToString();
  }
  Console.WriteLine((virus).ToString ());
  Console.Read();
}

for string multiplication, you can see this link

Click

Hiren solanki · Accepted Answer · 2010-10-29T21:07:00

Solution 4

That is because long is 64-bit signed Integer
and range of long datatype is -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807, It can't count more then this

My advise would be to use double instead will give you value in Exponential format and will not be overflowed.

Please vote and Accept Answer if it Helped.

Posted 29-Oct-10 21:07pm

Hiren solanki

Comments

Mostafa Elsadany 30-Oct-10 3:30am

ok thnx for help
but i try double giving my 1.000000 so this fraction
what i do

shakil0304003 30-Oct-10 3:32am

For removing fraction you can use, big integer multiplication, which link i gave in my answer. link -> http://www.learnxpress.com/addition-multiplication-of-very-long-integers.html