How to format a string with a decimal point every 3rd character....

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I am new to this site and c# (a VB programmer ) so please excuse any of my ignorances.

My question is this I have a string representation of a number.

The number can be between 0 and 999999999999

I need to represent the the string always in the format of 000.000.000.000

For example:

12567 would be 000.000.012.567
1379468 would be 000.001.379.468
4500078912 Would be 004.500.078.912

Etc.

I have tried many methods including using regex, string format, etc. Nothing seems to work.

Any help would be greatly appreciated.

Thank you.

What I have tried:

Private String OriginalString;

OriginalString = "132456";

String.Format(############,OriginalString);

.....

Posted 19-Jan-18 23:00pm

Member 13631520

Updated 19-Jan-18 23:17pm

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OriginalGriff · Accepted Answer · 2018-01-19T23:17:00

For starters, don't use strings to represent numbers: it's a PITA when you want to do something with them later. Always holds data in the appropriate datatype, and convert to that type as early as possible using the Parse, TryParse, and / or TryParseExact methods (reporting problems to the user as you go) and convert back to a string for presentation as late as possible.
The "early in" and "late out" design lets you use information about the users Locale and Culture which may not be available while processing or if you store the info.

Then it's just a matter of formatting the number for output:

long x = 4500078912;
Console.WriteLine("{0:00#\\.###\\.###\\.###}", x);
string output = String.Format("{0:00#\\.###\\.###\\.###}", x);

Thomas Daniels · Accepted Answer · 2018-01-19T23:10:00

Solution 1

There is a solution using regular expressions:

C#

string formatted = Regex.Replace(originalString, ".{3}", "$0.");

Posted 19-Jan-18 23:10pm

Thomas Daniels