I am trying to write a code to calculate square root upto 2 decimal places using loops.

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My code is as below:

Python

s = 18
x = 0.000
g = 0
a = -1
for n in range(0,3):
    while((x+(a/10**(n)))**2 <= s and x <= s/2 and a <= 9):
        a = a+1
        x = x + a/10**(n)
        g = g+1
        print(x)
        print(g)
        print(n)
        print(a)

y = format(x,'.2f')
y

What I have tried:

I am getting 4.00 as answer. I wanted to know why am I not able to go beyond 4.0 and check for 4.1 and so on.

Posted 26-Dec-17 8:20am

Ishita07

Updated 26-Dec-17 9:00am

Thomas Daniels

v2

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Richard MacCutchan 26-Dec-17 14:55pm

Please format your code properly between <pre> tags, so we can see the indenting.

2 solutions

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Thomas Daniels · Answer 1 · 2017-12-26T09:00:00

In Python 3, y is 4.20.

In Python 2, it is 4.00 indeed, so I assume you're using that version. And there is the cause: in Python 2, division between two integers returns an integer as well, whereas you actually want a floating-point number as result. (In Python 3, division is floating-point division by default and // does integer division)

There are two possible solutions to fix this:

One way is to make all your initial variables floats, like this:

Python

s = 18.0
x = 0.000
g = 0.0
a = -1.0

Now all divisions (e.g. a / 10) are float / int divisions, which result in a float.

Another option, which does not require the above, is to tell Python to use floating-point division in all cases, by adding this line to the top of your code file:

Python

from __future__ import division

Richard MacCutchan · Answer 2 · 2017-12-26T09:01:00

Solution 2

I just ran this and got the following output:

x:  0.0
g:  1
n:  0
a:  0
x:  1.0
g:  2
n:  0
a:  1
x:  3.0
g:  3
n:  0
a:  2
x:  3.3
g:  4
n:  1
a:  3
x:  3.6999999999999997
g:  5
n:  1
a:  4
x:  4.199999999999999
g:  6
n:  1
a:  5
y:  4.20

Posted 26-Dec-17 9:01am

Richard MacCutchan

I am trying to write a code to calculate square root upto 2 decimal places using loops.

2 solutions

Solution 1

Solution 2

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