How the output is 4321

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int i =43; printf("%d",(printf("%d",(printf("%d",i)))));

What I have tried:

My output is 434343. Can any one help me please

Posted 23-Apr-17 4:36am

Member 13100982

Updated 23-Apr-17 5:19am

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[no name] 23-Apr-17 11:16am

Help you with what?

Patrice T 23-Apr-17 11:19am

What is the question ?
No telegraphic style.

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OriginalGriff · Accepted Answer · 2017-04-23T05:18:00

No, your output is 4321:

printf("%d",(printf("%d",(printf("%d",i)))));
                          ^             ^
                            Prints "43" and returns the number of characters printed: 2
             ^                            ^
                Prints "2" and returns the number of characters printed: 1
^                                           ^
   Prints "1" and returns the number of characters printed: 1

It's the equivalent of saying:

i = printf("%d",i);
i = printf("%d",i);
printf("%d",i);

As the "innermost" function call has to be executed first.

jeron1 · Accepted Answer · 2017-04-23T05:19:00

Take a look here printf - C++ Reference[^]

int i =43; 
printf("%d",(printf("%d",(printf("%d",i)))));

the bold printf is done first and prints "43", the return value of the printf is 2 (as in 2 characters printed).

int i =43; 
printf("%d",(printf("%d",(printf("%d",i)>))));

this bold printf is next and the operand is 2 (the return value from the first call), and so the number "2" gets printed, the return value from this printf is 1 as only one character was printed.

int i =43; 
printf("%d",(printf("%d",(printf("%d",i)>))));

the bold printf here is done last with the number 1 as the operand, so "1" gets printed.

So the expected output would be "4321".

How the output is 4321

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