Help with simple php + css.. calling in a link through a function

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There's code in my project that links a button in the navigation to a Twitter account. I'm trying to duplicate this for Facebook. I already made a Facebook .li style in the CSS. The new FB button appears next to the Twitter btn, but I can't get it to link. I also created a function to make an input field for Facebook.

PHP

<?php if (get_option(THEME_PREFIX . "twitter_link")) { ?>
<li class="twitter"><a href="http://twitter.com/<?pho echo get_option(THEME_PREFIX . "twitter_link"); ?>"title"Twitter"></a></li>
<?php if (get_option(THEME_PREFIX . "facebook_link")) { ?>
<li class="facebook"><a href="http://facebook.com/<?pho echo get_option(THEME_PREFIX . "facebook_link"); ?>"title"Facebook"></a></li>

I'd appreciate any help!

Posted 28-Sep-10 18:30pm

aaacouncil

Updated 28-Sep-10 22:48pm

Sandeep Mewara

v2

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dawmail333 · Answer 1 · 2010-09-29T13:53:00

Solution 1

There are quite obviously some syntax errors in your code, but I assume they are just mistakes. Are you sure a valid URL is being produced?

Posted 29-Sep-10 13:53pm

dawmail333

Bryian Tan · Answer 2 · 2010-09-29T18:19:00

hello,

I didn't see where you close the first if statement. Seem like you have a nested if statement.

if (get_option(THEME_PREFIX . "twitter_link")) {
//twitter link

} --> try locate the closing bracket for the first if statement and append the new if statement below it.

if (get_option(THEME_PREFIX . "facebook_link")) {
//Facebook link

XML

<?php if (get_option(THEME_PREFIX . "twitter_link")) { ?>
<li class="twitter"><a href="http://twitter.com/<?pho echo get_option(THEME_PREFIX . "twitter_link"); ?>"title"Twitter"></a></li>
<?php } ?> //locate this
<?php if (get_option(THEME_PREFIX . "facebook_link")) { ?>
<li class="facebook"><a href="http://facebook.com/<?pho echo get_option(THEME_PREFIX . "facebook_link"); ?>"title"Facebook"></a></li>
<?php } ?

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