How to create model class for the mentioned XML tag ?

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How to create model class for the xml tag. On deserializing getting the exception there is an error in reflcetion type of Model class.
My Xml is as below:

XML

<advice_tags>
  
  <aclassname>SAV1 ACCOUNT</aclassname>
  <blockedbalance>0</blockedbalance>
  <acy>
    <blocked_acy>23</blocked_acy>
    <amount_acy>56</amount_acy>
  </acy>
  
</advice_tags>

My Model class for the above Xml Tag is as below:

C#

[XmlElement("ACLASSNAME")]
       public string ACLASSNAME { get; set; }
       [XmlElement("BLOCKEDBALANCE")]
       public string BLOCKEDBALANCE { get; set; }


       [XmlArray("ACY")]
       [XmlArrayItem("BLOCKED_ACY")]
       [XmlArrayItem("AMOUNT_ACY")]
       public List<string> ACY { get; set; }

But I am getting exception on desalinizing the same for the XmlArray attribute.

C#

MDL_UBSFile UBSFile = null;
                                  XmlSerializer serializer = new XmlSerializer(typeof(MDL_UBSFile));
                                  reader = new StreamReader(Path.Combine(UBSFilePath, FileName));
                                  dss.ReadXml(reader);
                                  reader.Close();

Posted 3-Aug-16 20:32pm

Ema112

Updated 3-Aug-16 21:42pm

Maciej Los

v6

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Thomas Nielsen - getCore · Answer 1 · 2016-08-03T21:42:00

Your xml become sensitive to big and small letters, so say

XML

<myclass>
   <myproperty>1</myproperty>
</myclass>

is not

C#

public class MyClass{
  public int MyProperty{ get;set;}
}

rather would be

C#

public class myclass{
  public int myproperty{ get;set;}
}

so what you need to do is match the way you wrote it

... (updating solution) ...
So if that doesn't work, i suggest going the other way about. Make the class first

and it is clear by observing your xml that a class AdviceTag could be generated with two simply types and one complex type called Acy with two values (Blocked and amount), perhaps like this:

C#

public class AdviceTag
    {
        public string AClassName { get; set; }
        public string BlockedBalance { get; set; }

        public Acy Acy { get; set; }
    }

    public class Acy
    {
        public string Blocked{ get; set; }
        public string Amount { get; set; }
    }

so that in place let's simply generate the xml by instantiating an instance of that class and serialize it

C#

var aTag = new AdviceTag { AClassName = "Sav1 Account", BlockedBalance = "0", Acy = new Acy { Amount = "56", Blocked = "23" } };

           var ser = new XmlSerializer(typeof(AdviceTag));

           string filename = Assembly.GetExecutingAssembly().Location;
           int pos = filename.LastIndexOf(@"\");
           filename = filename.Substring(0, pos +1) + "myfile.xml";
           using(var fs = new FileStream(filename, FileMode.Create, FileAccess.Write))
           {
               ser.Serialize(fs, aTag);
               fs.Flush();
               fs.Close();
           }

We're placing the serialized xml in same location as executing assembly and calling it myfile.xml, it then looks like this:

XML

<?xml version="1.0"?>
<AdviceTag xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <AClassName>Sav1 Account</AClassName>
  <BlockedBalance>0</BlockedBalance>
  <Acy>
    <Blocked>23</Blocked>
    <Amount>56</Amount>
  </Acy>
</AdviceTag>

And now what was the mistake?

Well your xml designates a complex type called acy containing two member properties, but you were struggleing to put them in an arraylist, where you don't have to.