Switch case condition

Question

1.00/5 (1 vote)

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How to provide method which have parameters in switch case:

C#

switch(input){
case"y":contact(no,value);
break;
}

when i am doing so its give me error. plz help

[Update with code from comment]

C#

Console.Write("You have cross the limit of shares.Do you want to continue?(Y/N)");
string input = Console.ReadLine();

switch (input)
{
    case "y":Calculateshare(share:, totalBalance:);

        break;

    case "n":

        break;
}

near Calculateshare the error is Argument missing in parameters.

What I have tried:

Trying to provide parameterized method in switch case.

Posted 26-Apr-16 23:58pm

@j@y123

Updated 27-Apr-16 1:42am

Patrice T

v2

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Comments

phil.o 27-Apr-16 5:59am

Please show us your actual code. "its give me error" does not indicate anything useful whatsoever.

RJ_Zed 27-Apr-16 6:03am

Provide us the exact code snippet and the error which you get. Do you need a generic method or just to resolve the error.

Karthik_Mahalingam 27-Apr-16 6:06am

what error?

@j@y123 27-Apr-16 6:15am

Console.Write("You have cross the limit of shares.Do you want to continue?(Y/N)");
string input = Console.ReadLine();

switch (input)
{
case "y":Calculateshare(share:, totalBalance:);

break;

case "n":

break;
}
near Calculateshare the error is Argument missing in parameters.

Patrice T 27-Apr-16 7:41am

I updated your question with this code.
Use Improve question to update your question.

BillWoodruff 2-May-16 2:31am

Please do not take the responsibility for updating the original question away from the OP. That just encourages dependency.

Patrice T 2-May-16 4:39am

I do it because it help me to read code :-)
And as a side effect, I get rewards in Editor category

6 solutions

Solution 5

C#

Calculateshare(share:, totalBalance:);

What is this syntax ? Can it be the problem ?

Posted 27-Apr-16 1:39am

Patrice T

Solution 2

You should make the called method as static to make use of it in switch case.

C#

static void Main()
       {
           char input = Convert.ToChar(Console.ReadLine());
           switch (input)
           {
               case 'y':
                   contact();
                   break;
               case 'x':
                   contact1();
                   break;

           }
           Console.ReadLine();
       }

       public static void contact()
       {
           Console.WriteLine("Hi am method 1");
       }
       public static void contact1()
       {
           Console.WriteLine("Hi am method 2");
       }

is working. Just check

Posted 27-Apr-16 0:29am

Divya RS

Comments

@j@y123 27-Apr-16 6:31am

The method which i define is in different class.

Solution 6

Here is basic examples

Click Here

And your code is also correct only need to remove colon ( : ) symbol from parameters.

Posted 27-Apr-16 1:42am

Shambhoo kumar

Updated 1-May-16 19:15pm

v2

Comments

Philippe Mori 27-Apr-16 22:06pm

Fix the emoticon if you want some vote greater than 1.

Shambhoo kumar 2-May-16 1:14am

i was not inserted emoticon symbol just i used colon (:) symbol but it's automatically shown there ( emotion symbol.

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Richard MacCutchan · Accepted Answer · 2016-04-27T00:07:00

Solution 1

See switch (C# Reference)[^] and Method Parameters (C# Reference)[^].

Posted 27-Apr-16 0:07am

Richard MacCutchan

BillWoodruff · Accepted Answer · 2016-04-27T00:39:00

Solution 3

try:

case "y":
contact(no,value);
break;

most likely one, or both of your parameters 'no and 'value are undefined.

if the method "contact" is defined in some other class, then you will be able to use it only if you have a valid reference to it ... which can happen in several different ways.

if 'contact is defined as a static method in a static class, then put the static class name in the method call: someStaticClassName.contact(no, value);

the compile error should give you information about the problem here.

Posted 27-Apr-16 0:39am

BillWoodruff

Comments

@j@y123 27-Apr-16 6:41am

Thank you it works.

BillWoodruff 27-Apr-16 9:58am

Remember that every Class, Struct, Method has a "virtual address:" AssemblyName/NameSpace/ClassName/????? ... most of the time you may not have to specify those because the current context is one where whatever object is accessible by a simple direct reference. But, when you use multiple NameSpaces, etc., you may need to specify the full "address." Of course, 'using directives' at the top of your .cs files may include the names of other name-spaces, or libraries (dll's) required.

It's like when you are in your "home town" you can say to someone: "I live on 19th. Street," you don't have to state the name of your province, district, city, etc. But, go to another country, and you may need to give a full address.

NameSpaces in .NET are another tool for organizing programs to achive encapsulation and separation of concerns. They allow you to use the same names for different purposes in different contexts ... or, of course, unique names.

Karthik_Mahalingam · Accepted Answer · 2016-04-27T00:41:00

verify your syntax

C#

static void Main(string[] args)
        { 
            Console.Write("You have cross the limit of shares.Do you want to continue?(Y/N)");
            string input = Console.ReadLine();

            switch (input)
            {
                case "y": Calculateshare(share: 5, totalBalance: 10);

                    break;

                case "n":

                    break;
            }

        }

        static void Calculateshare(int share, int totalBalance)
        {

        }

or

C#

  int share = 5;
            int totalBalance = 10;

            Console.Write("You have cross the limit of shares.Do you want to continue?(Y/N)");
            string input = Console.ReadLine();

            switch (input)
            {
                case "y": Calculateshare(share, totalBalance);

                    break;

                case "n":

                    break;
            }

Switch case condition

6 solutions

Solution 1

Solution 3

Solution 4

Solution 5

Solution 2

Solution 6

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