Password with more than 5 character at least one number, one character

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I am using javascript to validate password but it's fails the requirement. I need Password with More than 5 Character at least one number, one character

What I have tried:

var pwd = /(?=.*\d)(?=.*[a-z]).{6,}/;
var pwd = /^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+){6,}$/

both fail on test "King382413"

Posted 11-Apr-16 20:55pm

itsathere

Updated 12-Apr-16 0:30am

v2

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3 solutions

Solution 1

Don't try to use a single Regex - it's not at all simple.
Instead, do it in javascript as a number of checks: How to Build a Password Validator with JavaScript – Matt Litzinger[^]
That way, when your password requirements change (as they should, you should allow - if not insist on - special characters as well) it's a heck of a lot simpler to change them!

Posted 11-Apr-16 21:19pm

OriginalGriff

Comments

itsathere 12-Apr-16 3:25am

Yes, it fine but what about if i use regular expression like below but getting error ""#" is not valid at the start of a code block. Only identifiers, keywords, comments, "(" and "{" are valid." due to razor

var pwd = /^(?=.*[a-zA-Z])(?=.*\d)(?=.*[!@#$%^&*()_+])[A-Za-z\d][A-Za-z\d!@#$%^&*()_+]{6,}$/

Dave Kreskowiak 12-Apr-16 9:19am

You're demonstrating why OriginalGriff is saying what he said. If your password requirements change you have to change the RegEx expression. Look at the problems you're having making this work for your initial requirement! You can't do it. So when the password requirements change, you're going to be back at the same problem struggling to figure out a RegEx expression to cover the new requirements.

SIMPLIFY IT. Use separate tests. It's much easier to maintain and, therefor, less expensive to you.

Dave Kreskowiak 12-Apr-16 9:21am

We can't see your Razor code so it's impossible to tell you what you're doing wrong.

But, what I will say is if you've got javascript, it would be better to put that code in separate .js files and Include those scripts in the Razor code instead of trying to directly embed it. This makes your javascript code reuable for multiple views instead of just the one view page.

itsathere 12-Apr-16 11:23am

I have got the solution by putting @@ at @.Thanks for your reply.
previous version

var pwd = /^(?=.*[a-zA-Z])(?=.*\d)(?=.*[!@#$%^&*()_+])[A-Za-z\d][A-Za-z\d!@#$%^&*()_+]{6,}$/

new version

var pwd = /^(?=.*[a-zA-Z])(?=.*\d)(?=.*[!@@#$%^&*()_+])[A-Za-z\d][A-Za-z\d!@@#$%^&*()_+]{6,}$/

Solution 2

Try this,

^(?=.*?[0-9])(?=.*[!@#$%])[0-9a-zA-Z!@#$%0-9]{6,}$

Posted 11-Apr-16 23:05pm

deepankarbhatnagar

Comments

itsathere 12-Apr-16 5:14am

@ not support in mvc view due to razor engine. I have checked regex
var pwd = /^(?=.*[a-zA-Z])(?=.*\d)(?=.*[!@#$%^&*()_+])[A-Za-z\d][A-Za-z\d!@#$%^&*()_+]{6,}$/
if you are able to modify, reply.

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itsathere · Accepted Answer · 2016-04-12T00:30:00

Solution 3

JavaScript

 var pwd = /^(?=.*[a-zA-Z])(?=.*\d)(?=.*[!@@#$%^&*()_+])[A-Za-z\d][A-Za-z\d!@@#$%^&*()_+]{6,}$/

if (pwd.test(Passwordobj.value) == false) {
            errorPasswordobj.innerHTML = "More than 5 Character at least one number, one character.";
return false;
        }

Got idea from here

Posted 12-Apr-16 0:30am

itsathere

Updated 12-Apr-16 0:54am

v3