How do i write a program that solve this easy question ? ps : i am new in c++ programming

Question

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Find the sum of squares of individual digits of a number 'sqdnumber' and store the sum in variable 'sqdNumber_result'. E.g. if the number is 234, the sum is computed as (2*2 + 3*3 + 4*4 = 4 + 9 + 16 = 29)

What I have tried:

i have tried using loops but i cant reach the idea to make this program alive

Posted 10-Mar-16 20:57pm

Bashar Kahwaji

Updated 10-Mar-16 21:22pm

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4 solutions

Solution 2

once you are able to extract the n^th digit from the number, the task is trivial. One way is the following:

C++

while (i)
{
  int d = i % 10; // at each iteration d is one digit extracted from i
  i = i / 10;
}

Posted 10-Mar-16 21:11pm

CPallini

Solution 3

We don't do your HomeWork.
Advice:
- Start by learn properly the language, structures, loops, branch ...
- Learn some analyze methods, Dijkstra Top-Down method is a good start.
https://en.wikipedia.org/wiki/Top-down_and_bottom-up_design[^]
https://en.wikipedia.org/wiki/Structured_programming[^]
https://en.wikipedia.org/wiki/Edsger_W._Dijkstra[^]
https://www.cs.utexas.edu/users/EWD/ewd03xx/EWD316.PDF[^]
- Learn the Debugger.

Posted 10-Mar-16 21:22pm

Patrice T

Comments

Bashar Kahwaji 11-Mar-16 3:44am

i'm just asking about the idea i didn't ask any one to write the program for me!!

Solution 4

base on char*:

C++

char *base = "234";
int sqdNumber_result = 0;
for(int i = 0; i < strlen(base); i++)
{
   sqdNumber_result += ((base[i]-48) * (base[i]-48)); 
}

based on int:

C++

int base = 234;
int sqdNumber_result = 0;
while(base)
{
   sqdNumber_result += ((base % 10) * (base % 10));
   base /= 10;
}

its in my mind, but i think will work
i don't know what dataype you use as base

Posted 10-Mar-16 21:22pm

Taulie

Comments

Richard MacCutchan 11-Mar-16 3:37am

You do not help people by doing their homework for them. Helping them to think is fine, but doing it for them is not.

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«_Superman_» · Accepted Answer · 2016-03-10T21:10:00

The difficult part here is to extract the digits.
You can do this in a single loop.

Extract the digit in the units place by doing a mod 10 -> digit = number % 10.
To continue the loop reduce the number by dividing it by 10 -> number /= 10.

I'm sure you can figure out the rest by yourself.

Tip:
Using the debugger will be a great help.
But if you have trouble doing that, try outputting the values of each variable inside the loop.