Python if then statement trouble

I don't know if you define Y previously in your code project but from the included code, the most glaring error here is: you are asking

if X == Y

and you aren't specifying

Y

before hand.

So basically; if variable equal to undefined variable, execute below code:

print('[Nation] Rome has taken over Gaul')
print ('[Nation] Gaul has fallen into ruins.'):
else:
    print 'Gaul has defeated Rome'

However, how often is anything getting printed? It would be pretty unfortunate if you were getting false positives.... i.e. your y variable accidentally equals x and gives the intended positive return of program execution at sporadic times.


Perhaps defining y before hand would take away any ambiguity for us.

i.e.

y = f[0]
x = raw_input('[Rome] ---> [y/n]')
if x == y: 
 
	print '[Nation] Rome has taken over Gaul'
	print '[Nation] Gaul has fallen into ruins.'
	
 
 
    else:
    	print 'Gaul has defeated Rome'

I suggest you work through The Python Tutorial[^].

In this line:

if x == y:

You have not said y is a string but instead python thinks it is a variable. simply change that line to the following:

if x == "y" or x == "Y":

(Please note I added the case where Y is a capital letter)
Remember, strings have the quotes (") around them and variables do not! :)