How do I split the column data which are having special characters.

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SQL-Server-2008R2

Hi,
I have a column name City whose data is containing spl characters and space.
Ex.:My Table
1. Ahmedabad - CG Road
2. Ahmedabad-Satellite Road
2. Delhi - Malviya Nagar
3. Hyderabad - Kukatpally

I want to retrieve the data as per my output.
OutPut:
1. col1 =Ahmedabad
col2 = CG Road
2. col1 =Ahmedabad
col2 = Satellite Road
3. col1 =Delhi
col2 = Malviya Nagar
4. col1 =Hyderabad
col2 = Kukatpally

Please help me out in my query.
Here is my query which i tried to work but unable to display as required.

CASE
WHEN City LIKE '%-%' THEN LEFT(City, Charindex(' ', City) - 1) ELSE City
END as CityName,
CASE
WHEN City LIKE '%-%' THEN RIGHT(City, Charindex(' ', Reverse(City)) -1)
END as CityLocation

--
Thanks in Advance :)

Posted 18-Jun-15 0:49am

pn46

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3 solutions

Solution 2

Hi, please run this sql query , this will gives you the required output surely.

Thanks in advance

SQL

SELECT substring(City, 1, CHARINDEX('-',City)-1) CityName,
substring(City, CHARINDEX('-',City)+1, LEN(City)) CityLocation
FROM My_Table

Posted 18-Jun-15 1:08am

deepankarbhatnagar

Comments

pn46 18-Jun-15 7:44am

Hi Mr.deepankarbhatnagar,
Thank you for the help. But unfortunately i encountered with the below error.

Msg 537, Level 16, State 2, Line 2
Invalid length parameter passed to the LEFT or SUBSTRING function.

Solution 3

hi,

Use this one

SQL

SELECT city,
       Substring(city, 1, Charindex('-', city, 1) - 1)     AS col1,
       Substring(city, Charindex('-', city, 1)+1, Len(city)) AS col2
FROM   cp_locations_D_D

Thanks
Dhamu

Posted 18-Jun-15 3:32am

Dhamodharan A

Comments

Dhamodharan A 19-Jun-15 4:22am

May i know why you down voted my answer ,whats wrong on that ???

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OriginalGriff · Accepted Answer · 2015-06-18T01:07:00

Solution 1

Change the ' ' to '-':

SQL

SELECT
CASE WHEN City LIKE '%-%' THEN LEFT(City, Charindex('-', City) - 1) ELSE City END as CityName,
CASE WHEN City LIKE '%-%' THEN RIGHT(City, Charindex('-', Reverse(City)) -1) END as CityLocation
FROM Addresses

Posted 18-Jun-15 1:07am

OriginalGriff

Comments

pn46 18-Jun-15 7:44am

Thanks a ton for the help. :)

OriginalGriff 18-Jun-15 7:46am

You're welcome!