Why its giving true I mean I will have some other memory location and i2 have different it must give false

If you do:

Integer i = new Integer(10);
Integer i2 = new Integer(10);
System.out.println(i==i2);

then you'll probably get false.

If you do:

Integer i = Integer.valueOf(10);
Integer i2 = 10;
System.out.println(i==i2);

then you'll get true, because values between -128 and 127 are automatically cached:
Java gotchas - OWASP[^]
Chapter 5. Conversions and Promotions[^]

If you declare the variables as int rather than Integer, then you'll get true because you're performing a value equality test, not a reference equality test.

You have to understand that those 2 lines are 2 ways to say the same thing.

int i=new Integer(10);
int i2=10;

The 2 lines are integers of value 10, so they are equal.
Use the debugger and see by yourself.

There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
http://docs.oracle.com/javase/7/docs/technotes/tools/windows/jdb.html[^]
https://www.jetbrains.com/idea/help/debugging-your-first-java-application.html[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.