Java string method compilation

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I have a doubt in Java String syntax.. Java has a function for converting characters to lower case as String.toLowerCase() which "returns a String" with lower case characters.. But if we do not assign the above method to a String variable like:

Java

String a = "aBCd";

Java

a.toLowerCase(); // Do not cause any compilation error

Correct Way

Java

a = a.toLowerCase(); // a is assigned the value of updated string

Why does the first declaration not cause any compilation error?

What I have tried:

Understanding string method in Java..

Posted 6-Feb-18 7:33am

Akshit Gupta

Updated 6-Feb-18 9:17am

v6

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Richard MacCutchan · Accepted Answer · 2018-02-06T09:16:00

Solution 1

Because you are just calling a method, which is syntactically correct in almost all computer languages. The fact that you do not save the returned value is your choice as the developer. After all, the compiler almost always assumes that you know what you are doing.

Posted 6-Feb-18 9:16am

Richard MacCutchan

Comments

Maciej Los 6-Feb-18 15:34pm

I'm not able to say it better or even shorter.

Richard MacCutchan 6-Feb-18 15:59pm

:thumbsup: but I think you are being too kind.

Akshit Gupta 6-Feb-18 15:49pm

Thank you sir