How do I find all consecutive substrings in a string given two indices

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How do I find all consecutive substrings in a string given two indices

What I have tried:

def all_possible_substring(string, start, end){
  for ( i : [start:end+1] ){ // from index start to end
    for ( j : [i:end+1] ){ // from index i to end
      println( string[i:j]) // splice the string from i,j and print
    }
  }
}
all_possible_substring( "abcdef" , 0, 2) // test it off

Posted 5-Nov-17 19:56pm

Ankitha Rajput

Updated 6-Nov-17 0:49am

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CodingLover 6-Nov-17 3:06am

Can you post an example?

Suvendu Shekhar Giri 6-Nov-17 5:52am

Yes, please post one example of both input and output what you need.

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Richard MacCutchan · Answer 1 · 2017-11-06T00:49:00

It is easier than that. Your end index must never be greater than the end index of your string, so that is the value to check in your loop. Something like :

def all_possible_substring(string, start, end){
  WHILE (end < string.length - 1)
      println( string[start:end])
      start += 1
      end += 1
  }
}
all_possible_substring( "abcdef" , 0, 2) // test it off

Yes, I know this is not PHP, but the logic is the same.