How can I copy a char array in another char array?

Question

1.00/5 (1 vote)

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Hello,

Is there a method or a way to copy a char array (for example of size 8) in a char array (of size 64).

What I have tried:

I already tried using some methods like Array.Copy and copyto() but it didn't worked.
My result char array was always /0 /0 /0 /0 .....

public int CAN_DefineTransmit(int canNo, int iD, int cycleMs, int offsetMs, int length, char[] frame)
{
    int ret;
    this.ReadBuffer();
    this.CANDIAG_CommandBufferInit();

    this.buff.Param[1].IValue = canNo;
    this.buff.Param[2].IValue = iD;
    this.buff.Param[3].IValue = cycleMs;
    this.buff.Param[4].IValue = offsetMs;
    this.buff.Param[5].IValue = length;
    if ((length < 8 && length >= 0) || length > 8)
    {
        Array.Copy(frame, 0, this.buff.Param[3].FrameFD, 0, length);
    }
    else
    {
        Array.Copy(frame, 0, this.buff.Param[3].FrameFD, 0, 8);
    }

    // this.buff.Param[6].FrameFD = frame;
    ret = this.CANDIAG_Client_SendCommand(501);
    this.WriteBuffer();
    return this.CANDIAG_CommandBufferExit();
}

Frame FD is a char array of 64 declared in a structure.

Posted 28-Jun-17 21:22pm

Todiruta Costel Nicusor

Updated 28-Jun-17 21:40pm

v2

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Comments

Kornfeld Eliyahu Peter 29-Jun-17 3:26am

You should show your code...

2 solutions

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OriginalGriff · Accepted Answer · 2017-06-28T21:35:00

Solution 1

Try this:

C#

char[] input = "Hello! This is text.".ToCharArray();
char[] output = new char[64];
Array.Copy(input, output, input.Length);
for(int i = 0; i < output.Length; i++)
    {
    char c = output[i];
    Console.WriteLine("{0}:{1:X02}", char.IsControl(c) ? '*' : c, (int)c);
    }

Posted 28-Jun-17 21:35pm

OriginalGriff

Comments

Todiruta Costel Nicusor 29-Jun-17 5:23am

Thank You, it helped me.

OriginalGriff 29-Jun-17 5:32am

You're welcome!

Prifti Constantine · Accepted Answer · 2017-06-28T21:40:00

Solution 2

This example should work fine... Array.copy() copies the range of the source array to the specified array of your choice.
I hope this helps:

C#

char[] myarray = new char[5];
myarray2 = new char[64];
Copy(myarray, myarray2, 5);

Posted 28-Jun-17 21:40pm

Prifti Constantine

Comments

Todiruta Costel Nicusor 29-Jun-17 5:23am

Thank You, it helped me.

Prifti Constantine 29-Jun-17 5:32am

Glad to hear that!