Combination of numbers

Question

1.00/5 (1 vote)

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i need a combination like this
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 
1 2 3 4 5 6   8 
1 2 3 4 5   7 8 
1 2 3 4   6 7 8 
1 2 3   5 6 7 8 
1 2   4 5 6 7 8 
1   3 4 5 6 7 8 

For next iteration 
1 2 3 4 5 6 7 
1 2 3 4 5 6     9
1 2 3 4 5   7   9
1 2 3 4   6 7   9
1 2 3   5 6 7   9
1 2   4 5 6 7   9
1   3 4 5 6 7   9

like wise till
1   3 4 5 6 7 8 
1   3 4 5 6 7   9
1   3 4 5 6   8 9
1   3 4 5   7 8 9
1   3 4   6 7 8 9
1   3   5 6 7 8 9
1     4 5 6 7 8 9

What I have tried:

I have tired but not getting the logic. Please help me.

Posted 7-Feb-17 18:35pm

R!sh!

Updated 7-Feb-17 21:59pm

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Comments

Peter Leow 8-Feb-17 1:09am

"I have tired but not getting the logic" then show what you have tried.

OriginalGriff 8-Feb-17 1:59am

What have you tried?
Where are you stuck?
What help do you need?

3 solutions

Solution 1

Look at the digits arranged as a square

(1,1)                      (1,9)
  \                         /
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
   1  2  3  4  5  6  7  8  9
  /                         \ 
(9,1)                      (9,9)

Then at iteration k you must show all the square items, but:

The ones of column k, that is (i,k).
The ones on the diagonal, that is (k, 10-k).

Posted 7-Feb-17 21:25pm

CPallini

Solution 2

Quote:
I have tired but not getting the logic. Please help me.

First help yourself with method.
You have noted that
You don't understand the logic:
- try to draw by hand the result wanted for each iteration in order.
- try to analyze the differences between each iteration an note what t(he changes are.
By this point, you should have got the logic, otherwise, talk to your teacher.

are you sure about the 9 in first iteration ?

Posted 7-Feb-17 21:47pm

Patrice T

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R!sh! · Accepted Answer · 2017-02-07T21:59:00

Solution 3

#include<stdio.h>

int main()
{
	int a[9]={1,2,3,4,5,6,7,8,9};
	int i,j=9,k;
	
	while(j>0)
	{
		for(i=1;i<8;i++)
		{
			for(k=0;k<9;k++)
			{
				if(k!=i&&k!=j)
			{
				printf("%d",a[k]);
				
			}
			else
			{
				printf(" ");
				continue;
			}
			}
			printf("\n");	
		}
		printf("\n");
		j--;
	}
	return 0;
}

Posted 7-Feb-17 21:59pm

R!sh!

Comments

Patrice T 8-Feb-17 4:08am

A question and a solution without a single sentence!
Is it your solution or code that don't work ?

R!sh! 8-Feb-17 4:14am

my solution. :)

Patrice T 8-Feb-17 4:17am

So, use Accept answer (near "Solution 3") to signal it's solved and to close the question.

R!sh! 17-Feb-17 0:18am

can you give your answer please??

R!sh! 8-Feb-17 4:14am

finally i did it. :D

Patrice T 8-Feb-17 11:35am

I see that your program do not match the example of the question, first iteration is not the same (the 9 on first line).

R!sh! 16-Feb-17 23:55pm

it is coming in reverse order.