[C#]how to check if an exe is open or closed

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I did this code and I put in a timer in order to check if the exe is open or closed.
I create a class and put it inside and then call it after in Winforms.
Here is the code:

C#

private static WINDOWPLACEMENT GetPlacement(IntPtr hwnd)
        {
            WINDOWPLACEMENT placement = new WINDOWPLACEMENT();
            placement.length = Marshal.SizeOf(placement);
            GetWindowPlacement(hwnd, ref placement);
            return placement;
        }

        [DllImport("user32.dll", SetLastError = true)]
        [return: MarshalAs(UnmanagedType.Bool)]
        internal static extern bool GetWindowPlacement(
            IntPtr hWnd, ref WINDOWPLACEMENT lpwndpl);
        internal enum ShowWindowCommands : int
        {
            Hide = 0,
            Normal = 1,
            Minimized = 2,
            Maximized = 3,
        }

        [Serializable]
        [StructLayout(LayoutKind.Sequential)]
        internal struct WINDOWPLACEMENT
        {
            public int length;
            public int flags;
            public ShowWindowCommands showCmd;
            public System.Drawing.Point ptMinPosition;
            public System.Drawing.Point ptMaxPosition;
            public System.Drawing.Rectangle rcNormalPosition;
        }

        [DllImport("user32.dll")]
        private static extern bool ShowWindowAsync(IntPtr hWnd, int nCmdShow);
        public static void MaximizeWindowIfMinized(string windowName,Timer tim,FlowLayoutPanel f1)
        {
            tim.Start();
            Button btn = new Button();
            Process[] procs = Process.GetProcesses();
            try
            {


                foreach (Process proc in procs)
                {
                    if (proc.ProcessName.Contains(windowName))
                    {
                        var placement = GetPlacement(proc.MainWindowHandle);
                        Console.WriteLine(placement.showCmd.ToString());

                        if (placement.showCmd == ShowWindowCommands.Normal)
                        {

                            btn = new Button();
                          //  btn.Width = 150;
                          //  btn.Height = 120;
                            f1.Controls.Add(btn);
                         //   btn.Left = 500;                           
                          //  btn.Visible = true;
                            // btn.Click += button1_Click(windowName);
                            tim.Stop();
                        }
                        tim.Start();

                         if (placement.showCmd == ShowWindowCommands.Hide)
                        {
                            btn.Visible = false;
                            tim.Stop();

                        }

                    }
                }
            }
            catch
            {

            }

        }

Here, the problem is that it is looping in the timer and I don't know how to control it...
At each time an app is clicked the button will be created and if the app is closed the button must disappear.

Thank you.

What I have tried:

My idea is to create a button only if one does not already exist for the process in question. I may do that by associating the process ID (or perhaps Process to the button (via Tag property) and then searching the buttons for each process. I don't want to have duplicates. That will at least resolve the replicating button issue. What do you think ?

Posted 6-Sep-16 7:06am

TatsuSheva

Updated 6-Sep-16 11:21am

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Comments

Philippe Mori 6-Sep-16 13:33pm

It is hard to understand what you want to do and the code does not make any sense as it would break for sure if 2 windows have the same name...

TatsuSheva 6-Sep-16 13:41pm

it is simple, in my application I want to open exe applications like Notepad etc, so when the notepad is open, a button is created and when the notepad is closed the button disappear simply and when we click on the button if the window of the notepad is open it will be minmized and whenb the window is minimized it will be restored.

Philippe Mori 6-Sep-16 15:30pm

Windows already put button for opened application in the taskbar...

johannesnestler 8-Sep-16 8:25am

I don't get what you do with the timer here? start-stop inside a Loop? Can you please explain us what you want to do - because for me your (timer-) code makes no sense... you mentioned (other comments) that your problem is with this timer, but then you say that dublicate Windows are open (another problem, you didn't write correct code for this, other solutions already showed you)...

johannesnestler 8-Sep-16 8:27am

@ idea with process-id: this ID is unique for every process - so 10 instances of Notepad = 10 different process id's..

TatsuSheva 8-Sep-16 8:38am

Yes, I used the ID for this, now my only problem is when I close the window of Notepad for example the button can't be hidden have a look here for more informations about my problem : https://social.msdn.microsoft.com/Forums/en-US/bd862423-13b9-4458-b270-c005d31e48a8/how-to-restore-the-window-of-an-exems-word-excel-etc-in-c?forum=csharpgeneral

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xXxRevolutionxXx · Accepted Answer · 2016-09-06T11:21:00

When an executable is open in the system... there will be a process with the exact same name as the file. For example if you are looking for an exe file which is called: SystemCleaner.exe you can find it as a process with the name: SystemCleaner.
Accordingly if the file name has a space, for example: System Cleaner.exe Then you will looking for a process called: System Cleaner.

You can count how many processes with a specific name exist in the system.. with the following lines of code(in C#):

C#

int counter = 0;
        foreach (Process process in Process.GetProcessesByName("SystemCleaner"))
        {
            counter++;
        }
	if(counter > 0)
          {
             YourButtonName.Visible = true;
          }
          else
          {
             YourButtonName.Visible = false;
          }