Xml serialization C# I get error when I deserialize

Question

0.00/5 (No votes)

See more:

Hello these are my serialization and deserialization methods in c#. When I deserialize an object or something I get Error.

C#

public byte[] Serialize<T>(T ob)
        {
            System.Xml.Serialization.XmlSerializer xs = new System.Xml.Serialization.XmlSerializer(ob.GetType());
            MemoryStream ms = new MemoryStream();
            xs.Serialize(ms, ob);
            string xmlData = System.Text.Encoding.ASCII.GetString(ms.ToArray(), 0, ms.ToArray().Length);
            return ms.ToArray();
        }

public T XMLDeSerialize<T>(byte[] data)
        {
            string xmlData = System.Text.Encoding.ASCII.GetString(data,0,data.Length);
            System.Xml.Serialization.XmlSerializer xs = new System.Xml.Serialization.XmlSerializer(typeof(T));
            MemoryStream ms = new MemoryStream();
            ms.Write(data, 0, data.Length);
            ms.Position = 0;
            XmlReader rdr = XmlReader.Create(ms);
            ms.Position = 0;
            T t = (T)xs.Deserialize(rdr);
            return t;
        }

What I have tried:

I tried the methods above and could not managed to work. I cant find any solution.

Posted 10-Aug-16 9:08am

Eren Yatkin

Updated 10-Aug-16 9:58am

v3

Add a Solution

Comments

Kschuler 10-Aug-16 15:52pm

What error do you get?

Eren Yatkin 11-Aug-16 2:50am

I was getting "unexpected XML Error (0,0) ....but now these solutions working very well

Kschuler 11-Aug-16 13:45pm

Glad someone helped you. Just remember next time to include what error you got. It makes it a lot easier to narrow down the problem. :)

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Accepted Answer · 2016-08-10T09:54:00

Firstly, get rid of the two xmlData lines. You're not using the variable, so there's no need for it.

Secondly, after writing the data to the MemoryStream, you need to move the "current position" back to the start of the stream:

C#

ms.Write(data, 0, data.Length);
ms.Seek(0L, SeekOrigin.Begin);

With that change in place, your methods work perfectly:

C#

public byte[] Serialize<T>(T ob)
{
    var xs = new System.Xml.Serialization.XmlSerializer(ob.GetType());
    var ms = new MemoryStream();
    xs.Serialize(ms, ob);
    // string xmlData = System.Text.Encoding.ASCII.GetString(ms.ToArray(), 0, ms.ToArray().Length);
    return ms.ToArray();
}
 
public T DeSerialize<T>(byte[] data)
{
    // string xmlData = System.Text.Encoding.ASCII.GetString(data,0,data.Length);
    var xs = new System.Xml.Serialization.XmlSerializer(typeof(T));
    var ms = new MemoryStream();
    ms.Write(data,0,data.Length);
    ms.Seek(0L, SeekOrigin.Begin); // <-- Add this line
    T t = (T)xs.Deserialize(ms);
    return t;
}

Eren Yatkin · Accepted Answer · 2016-08-10T09:53:00

Solution 1

I found the solution.

I just removed

C#

ms.Position = 0

before

C#

T t = (T)xs.Deserialize(rdr);

İt worked like a charm.

Posted 10-Aug-16 9:53am