how to overload the functions

The fact that you can't overload on return type doesn't mean you can't simplify the process a bit under certain circumstances, e.g. if your return type is constructible from your input type.

template <typename T> T get(int i)
{
	return T(i);
}

int main()
{
	int i = get<int>(65);
	char c = get<char>(65);

	return 0;
}

The code above might be mistaken for an overload when in fact it's not. You will have to specify the return type when you call the function as the template argument. Sometimes this can be useful, but in effect, it is not different from implementing one method for each return type, like int getInt(int i) and char getChar(int i).

Hi,

The code wont compile..
U will get be given C2556 saying "The Overloaded func have different return types but the same parameter list".

Your function should have "Distinct" formal parameter list in compile time polymorphism(Function Overloading).

Apart from the above, your sum() functions are declared private and cannot be called in main - you'll get compiler error there if you don't declare them as public.

Regarding your question, if you go define void sum(int) and void sum(char), then your call sum(65) would call the int variant: integer constants are always assumed to be of type int, unless they are too big to fit into an int.

You can have, instead of an overload, a single function that returns a data structure with all the types you want. Simply use the structure member for the type you wish to use at any given time.

struct Rvals {
  int  i;
  char c;
} typedef rvals;

and then use the i or c member, as you wish, or both, from a single call.