Write a program to check a string is palindrome or not.

Question

1.00/5 (3 votes)

See more:

C++

#include<iostream>
using namespace std;

int main( )
{
    char str[80];

    cin.getline(str, 80);
	
    int l;     
    for(l = 0; str[l] != '\0'; l++);

    int i;
    for(i = 0; (i < l/2) && (str[i] == str[l - i - 1]); i++);

    if(i == l/2)
        cout << "Palindrome";
    else
        cout << "Not a palindrome";
	
    return 0;
}

For Example if the word is "gig" then it is palindrome but if the word is "Gig" then it is not working.

Can anyone edit the code so that It can accept both capital and small letter.

Posted 23-Jan-16 7:11am

Member 12282592

Add a Solution

Comments

nv3 23-Jan-16 13:20pm

Probably not. This task is so incredibly difficult that probably no one else except yourself will be able to do that. So, the world is waiting for you to solve that problem.

Sergey Alexandrovich Kryukov 23-Jan-16 13:22pm

Start with writing a function "IsAPalindrome". You did not even try it, wrote something in "main".
—SA

Sascha Lefèvre 23-Jan-16 13:22pm

Take a look at all the functions for string manipulation. There should be one which will convert a string to all upper case or all lower case...

Patrice T 23-Jan-16 13:32pm

Your homework, not our's

4 solutions

Solution 1

A common way of doing this, is using the tolower() function.

So run the input trough it, and use your algorithm and you are done.

Posted 23-Jan-16 7:23am

KarstenK

Solution 2

Please see my comment to the question.

And yes, "Gig" is not a palindrome, in the sense you defined it. This is because 'g' != 'G'. If you want a case-insensitive palindrome test, use case-insensitive check-up. Before comparing two characters, convert both to lower case or to upper case. Please see:
tolower - C++ Reference[^],
toupper - C++ Reference[^].

—SA

Posted 23-Jan-16 7:26am

Sergey Alexandrovich Kryukov

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

PIEBALDconsult · Accepted Answer · 2016-01-23T08:00:00

Solution 3

As you are using a lower-level language, I suggest using a lower-level technique; it should impress your teacher very much.
In the ASCII encoding, the difference between uppercase letters and their lowercase counterparts, is one bit.

For example:

A == 65 == 1000001
a == 97 == 1100001
__________________
XOR  32    0100000

I'm sure you can easily implement a function to test two characters, and if they are letters, then to perform a bit-wise comparison that ignores that one bit.

Your overall implementation will still need to ignore punctuation and such.

Go hang a salami, I'm a lasagna hog!

Posted 23-Jan-16 8:00am

PIEBALDconsult

Updated 23-Jan-16 8:07am

v5

Comments

Sergey Alexandrovich Kryukov 23-Jan-16 14:24pm

Works just for English. I appreciate it, but it's hard to call a solution for one language (okay, maybe for very few languages) a solution...
—SA

PIEBALDconsult 23-Jan-16 14:26pm

As I said: "ASCII"

Sergey Alexandrovich Kryukov 23-Jan-16 14:27pm

I know, you are perfectly right. Anyway, it's important to know. The inquirer should decide what to use.
—SA

Philippe Mori 23-Jan-16 14:27pm

Seriously, what should we vote for that... In a sense, user get the kind of answer he merit given its question! On the other hand, no one should ever do that in real-life application.

Sergey Alexandrovich Kryukov 23-Jan-16 14:30pm

I up-voted just for the demonstration of the technique. Of course, as a practical solution it cannot be considered acceptable, that's why I mentioned in my comment above: "it's hard to call a solution"...
—SA

PIEBALDconsult 23-Jan-16 14:49pm

No reason to vote at all.

Member 12282592 · Accepted Answer · 2016-01-23T14:57:00

Solution 4

Finally I executed by using && statement simply like Either-or statement..

Thanks for your comments.

Posted 23-Jan-16 14:57pm

Member 12282592