how to auto increment of alphanumeric number and special characters using c#

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C#

static float billno = 2000;
billno = billno + 1;
textBox1.Text = billno.ToString();

Posted 17-Dec-15 0:56am

MI_KRISHNAN

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Andreas Gieriet 17-Dec-15 7:04am

So what is the question?
This is completely unclear. What do you try to achieve? You increment already, right?
Andi

MI_KRISHNAN 17-Dec-15 7:07am

I need auto Increment like "ICPL/15/CL0055/M-01"
"ICPL/15/CL0055/M-02","ICPL/15/CL0055/M-03".....etc what to do

Andreas Gieriet 17-Dec-15 7:14am

So you need a function which identifies the trailing number in a given string and increment that number? What if there is no trailing number? What if the number has less positions than needed, e.g. ABC-0, ... ABC-9, ABC-10 (makes two digits out of initially one)? Is it supposed to respect leading zeros? E.g. UVW-01, ... UVW-09, UVW-10 (or UVW-010)?
Cheers
Andi

MI_KRISHNAN 17-Dec-15 7:22am

Initially starts with 01,02,03 and goes on upto 999

MI_KRISHNAN 17-Dec-15 7:46am

I have another doubt
static float billno = ICPL/15/CL0055/M-01;
billno = billno + 1;
textBox1.Text = billno.ToString();

is it possible

BillWoodruff 17-Dec-15 12:36pm

No, that's not a valid float you try to assign.

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Andreas Gieriet · Accepted Answer · 2015-12-17T01:30:00

How about this?

C#

// Parses the given argument for a trailing number, increments that number by 1.
// Returns the newly creates string with the incremented number or null if there is no number to increment.
// Leading zeros are used up if a carry occurs.
// If there is no leading zeros, if a carry occurs, the number of digits is increased by one.
static string TryToIncrement(string tag)
{
    string result = null;
    Match m = Regex.Match(tag, @"^(.*?)(\d+)$");
    if (m.Success) {
        string head = m.Groups[1].Value;
        string tail = m.Groups[2].Value;
        string format = new string('0', tail.Length);
        int incremented = int.Parse(tail) + 1;
        result = head + incremented.ToString(format);
    }
    return result;
}

Cheers
Andi