Rotaing a Line Around its midpoint in mfc

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Hi there,

I'm tring to rotate a line in mfc., around its center.
this should be rotated as i click the mouse and move it.
heres the code for it.
please help me put.

where NewPoint is the mouse click point
and m_newStart is line start point

C#

double distY=abs(m_NewPoint.y);
double distX=abs(m_NewPoint.x);
double theta=(abs(atan(distY/distX))*180/3.14);

m_newStart.x  = MdPt.x + (StPt.x-MdPt.x)*(cos(theta)) - (StPt.y-MdPt.y)*(sin(theta));
m_newStart.y  = MdPt.y  +  (-1)*(StPt.x-MdPt.x)*(sin(theta)) - (StPt.y-MdPt.y) * cos(theta));

m_newEnd.x  = MdPt.x -  (StPt.x-MdPt.x)*(cos(theta)) + (StPt.y-MdPt.y)*(sin(theta));
m_newEnd.y  = MdPt.y  -  (-1)*(StPt.x-MdPt.x)*(sin(theta)) + (StPt.y-MdPt.y)*(cos(theta));

Posted 19-Apr-15 19:57pm

Member 11484810

Updated 19-Apr-15 20:23pm

Kenneth Haugland

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Style-7 · Answer 1 · 2015-04-20T00:49:00

Solution 1

Calculate X and Y by this code (java). Use sin and cos in C++ (include math.h).

SQL

 x = center + radius * Math.sin( angle );
 y = center - radius * Math.cos( angle );
}

Posted 20-Apr-15 0:49am

Style-7

Comments

Member 11484810 20-Apr-15 6:52am

there's no radius over here.
And Does it apply to both the point co-ordinates??

Style-7 20-Apr-15 7:49am

radius = line lengh
center = coord. of mouse