How to generate random number in c# using random function, new/next number is grater than previous one...?

If you have to generate a finite sequence of increasing random numbers then you might follow this approach: generate the numbers using the standard random generator and store them into an array. Finally sort the array and use its items as the required (increasing) sequence.

Hi,

You can generate an initial random number and then sum that number to the previous generated one.

Random r = new Random();
List<double> numbers;
numbers.Add(r.next());
for(int i = 0;i<whatever_limit;i++){
numbers.Add(r.Next + numbers[i]);
}

Hope this helped.

LG

Here's a function that will generate a list in ascending order of randomly chosen integers in a certain range; every value in the list will be unique(no duplicates):

// requires Linq !
using Linq;

public List<int> generateRandomList(int sizeOfList, int min, int max)
{
    // add #1 to max value, so results include max value
    max++;

    // create, seed the random generator
    Random RandomGenerator = new Random(Guid.NewGuid().GetHashCode());
    
    List<int> randomIntResults = new List<int>();
    
    int currentInt = RandomGenerator.Next(min, max);
    
    for(int x = 0; x < sizeOfList; x++)
    {
        // keep going until you have a value that's not already in the List
        while (randomIntResults.Contains(currentInt))
        {
            currentInt = RandomGenerator.Next(min, max);
        }
        
        randomIntResults.Add(currentInt);
    }
    
    // use Linq to order the results in ascending order
    return randomIntResults.OrderBy(item => item).ToList();
}

If I wanted a List of 100 integers in the range 1~1000 chosen randomly:

List<int> randomInt100 = generateRandomList(100, 1, 1000);

Note there's no argument checking done above: you could do something stupid that would create an endless loop, like:

List<int> randomInt100 = generateRandomList(100, 1, 10);

try this :

private string GetRandomString()
        {
            Random rand = new Random((int)DateTime.Now.Ticks);
            int randomIndex1 = rand.Next(100, 999);
            int randomIndex2 = rand.Next(10000, 99999);
            string randstring = RandomString(3);
 
            string result = "#" + randstring + "-" + randomIndex1.ToString() + "-" + randomIndex2.ToString();
            return result;
        }
 
        private static Random random = new Random((int)DateTime.Now.Ticks);
        private string RandomString(int size)
        {
            StringBuilder builder = new StringBuilder();
            char ch;
            for (int i = 0; i < size; i++)
            {
                ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
                builder.Append(ch);
            }
 
            return builder.ToString();
        }

U can also refer this link

http://stackoverflow.com/questions/1122483/c-sharp-random-string-generator[^]