How to compute time format in gridview?

Question

1.00/5 (1 vote)

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I have three columns in my gridview.
The first and second column has a time format . example : 19:00 | 21: 00
and on the third column should be the total time in the first and second column.

I tried this:

VB

For i As Integer = 0 To gridview.Rows.Count - 1
               gridview.Rows(i).Cells(3).Text = gridview.Rows(i).Cells(0).ToString - gridview.Rows(i).Cells(1).ToString
           Next

but it is not working.
Can anyone give me other way?
Thanks !

Posted 28-Sep-14 21:19pm

NekoNao

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Comments

Gihan Liyanage 29-Sep-14 3:45am

This is code in C#
http://net4urhelp.wordpress.com/2012/01/04/calculate-hours-and-minutes-of-gridview-column-c-asp-net/[^]

4 solutions

Solution 1

In RowDataBound [^]event calculate the difference for each row

OR

Return the difference from your dataSource (database?) and simply bind the column to existing difference

OR

Use jQuery

OR

Add template field calling static (or protected) function from your server side code calculating the value
(example:

XML

<asp:TemplateField HeaderText="Total" ItemStyle-HorizontalAlign="Center" >
   <ItemTemplate>
      <%# GetDifference((Eval("time2"), Eval("time1")) %>
   </ItemTemplate>
</asp:TemplateField>

)

In all the cases you have to use DateDiff function (exists in SQL Server, there must be equivalent in other databases). Also exists in .net... pick your solution.

Posted 28-Sep-14 21:29pm

Sinisa Hajnal

Updated 28-Sep-14 21:31pm

v4

Comments

NekoNao 29-Sep-14 3:41am

Thanks ! I did the "Return the difference from your dataSource (database?) and simply bind the column to existing difference"

But i have a problem.

18:00 - 19:30 = should be "1.30" right? but in databind , its only 1. What should i do?

Sinisa Hajnal 29-Sep-14 3:45am

Are you receiving errors? And no: it should be 1.5 :) 1.30 would be 1 hour and 20 minutes...

I would say you need to use minutes in datediff and divide with 60 - datediff counts whole (integer) steps of your time unit (and 19:30 - 18:00 equals in hours 19 - 18)

Tiwari Avinash 29-Sep-14 5:24am

select right('00'+convert(varchar,datediff(HOUR,CONVERT(datetime,'18:00',103),CONVERT(datetime,'19:30',103))),2)
+':'+right('00'+
convert(varchar,datediff(MINUTE,CONVERT(datetime,'18:00',103),CONVERT(datetime,'17:30',103))),2)

if it helps please mark it as answer

Solution 3

You can do it easily from SQL DB as

SQL

select right('00'+convert(varchar,datediff(HOUR,CONVERT(datetime,'18:00',103),CONVERT(datetime,'19:30',103))),2)
+':'+right('00'+
convert(varchar,datediff(MINUTE,CONVERT(datetime,'18:00',103),CONVERT(datetime,'17:30',103))),2)

if it helps please mark it as answer

Posted 28-Sep-14 23:25pm

Tiwari Avinash

Solution 4

Please try this,

C#

protected void gvGridTime_RowDataBound(object sender, GridViewRowEventArgs e)
        {
            if (e.Row.RowType == DataControlRowType.DataRow)
            {
                DateTime dateFrom = Convert.ToDateTime(e.Row.Cells[1].Text);
                DateTime dateTo = Convert.ToDateTime(e.Row.Cells[2].Text);
                var diff = dateTo.Subtract(dateFrom);
                e.Row.Cells[3].Text = Convert.ToDateTime(diff.ToString()).ToString("hh:mm:ss");
            }            
        }

Posted 28-Sep-14 23:59pm

Manikandan MAC

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NekoNao · Accepted Answer · 2014-09-28T21:45:00

Solution 2

Okay. I found the solution here. And it was so easy . TIME DIFFERENCE IN MYSQL[^]

Posted 28-Sep-14 21:45pm

NekoNao

Comments

Sinisa Hajnal 29-Sep-14 3:52am

And you couldn't have used that before asking the question because...?

NekoNao 29-Sep-14 4:57am

Because I haven't got any idea at all. but thanks to you . i got an idea. I didnt think of using query at first but then you said "Return the difference from your dataSource (database?) and simply bind the column to existing difference".

Sinisa Hajnal 29-Sep-14 6:26am

Well, glad to be of help :)