How to distinct more than one column using sql server?

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SQL-Server-2008R2

SQL

select distinct MRP.[date],FT.feedtype,round(MRP.rateperkg,3) as Rateperkg from
    K_FS_FeedMrpDetails MRP inner join K_FPS_feedtype FT on FT.sno=MRP.feedtype
    where MRP.[date] between '2013-08-09 00:00:00.000' and '2014-08-25 00:00:00.000' and
    MRP.state = 1  and MRP.rateperkg != 0
    group by ft.feedtype,mrp.rateperkg order by MRP.[date] desc

In my query has same column values feedtype and rateperkg..

Now i want to distinct the these two columns ...how can i do this?

Please help me

Posted 24-Aug-14 20:08pm

ramaraog96

Updated 24-Aug-14 20:20pm

v3

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coded007 25-Aug-14 2:15am

can you give examples for column values for better understanding ?

[no name] 25-Aug-14 2:17am

date feedtype Rateperkg
2014-08-20 00:00:00.000 BF Pellet 31.8
2014-08-20 00:00:00.000 BPS 34
2014-08-20 00:00:00.000 Broiler Concentrate 35% 45.9
2014-08-20 00:00:00.000 BS 32.8
2014-08-20 00:00:00.000 Layer Grower - Gold 28.7
2014-08-20 00:00:00.000 LC Phase 1 32.4
2014-08-20 00:00:00.000 LC Phase 2 30.4

2014-08-18 00:00:00.000 BF Pellet 31.8
2014-08-18 00:00:00.000 BPS 34
2014-08-18 00:00:00.000 Broiler Concentrate 35% 45.9
2014-08-18 00:00:00.000 BS 32.8
2014-08-18 00:00:00.000 Layer Grower - Gold 28.7
2014-08-18 00:00:00.000 LC Phase 1 32.4
2014-08-18 00:00:00.000 LC Phase 2 30.4

In this example Feed type and feed rates are same ...Now we want to write the distinct two columns.

_Asif_ 25-Aug-14 4:38am

Please show us your expected output

[no name] 25-Aug-14 5:00am

In my above example shows "same rates added but dates are different"
Now My output show only one date feedtype rates

date feedtype Rateperkg
2014-08-18 00:00:00.000 BF Pellet 31.8
2014-08-18 00:00:00.000 BPS 34
2014-08-18 00:00:00.000 Broiler Concentrate 35% 45.9
2014-08-18 00:00:00.000 BS 32.8
2014-08-18 00:00:00.000 Layer Grower - Gold 28.7
2014-08-18 00:00:00.000 LC Phase 1 32.4
2014-08-18 00:00:00.000 LC Phase 2 30.4

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PhilLenoir · Answer 1 · 2014-08-25T04:01:00

What date do you want, earliest, latest? I've assumed most recent:

select MAX(MRP.[date]) AS LatestDate,FT.feedtype,round(MRP.rateperkg,3) as Rateperkg from
K_FS_FeedMrpDetails MRP inner join K_FPS_feedtype FT on FT.sno=MRP.feedtype
where MRP.[date] between '2013-08-09 00:00:00.000' and '2014-08-25 00:00:00.000' and
MRP.state = 1 and MRP.rateperkg != 0
group by ft.feedtype,mrp.rateperkg
order by LatestDate desc