how to change visibility of Image with right click

Question

4.00/5 (1 vote)

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I have two Images.
My XAMl code:

<Image Height="13" HorizontalAlignment="Left" Margin="284,236,0,0" Name="CBoff2"  Stretch="Fill" VerticalAlignment="Top" Width="18" Source="/ConfigurationWindowsDemo;component/Images/SymbolsOFF1.jpg"/>
<Image Height="13" HorizontalAlignment="Left" Margin="284,236,0,0" Name="CB2"  Stretch="Fill" VerticalAlignment="Top" Width="18"  Source="/ConfigurationWindowsDemo;component/Images/SymbolsON.jpg" />

What I Want is when we right click to "CB2", "CBoff2" should be visible and vice Versa. How can we do that?

Posted 7-Mar-11 18:35pm

amitkarnik2211

Updated 7-Mar-11 22:32pm

v4

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Comments

JF2015 8-Mar-11 0:38am

Added code formatting.

amitkarnik2211 8-Mar-11 1:27am

I tried this in my Xmal.cs
public void Cb1on(object sender, MouseButtonEventArgs e)
{
Visibility Image = Collapsed;
}
but not working

2 solutions

Solution 1

I don't see any event handler in your image control.
You need to add one.

Posted 7-Mar-11 23:04pm

Debojyoti Majumder

Comments

amitkarnik2211 8-Mar-11 5:10am

These are the event handlers I added Mouse down mouse enter and Mouse Leave are working fine as required
<Image Height="12" HorizontalAlignment="Left" Margin="203,238,0,0" Name="CBoff1" Stretch="Fill" VerticalAlignment="Top" Width="16" MouseDown="CB1_Click" MouseEnter="CB1_MouseEnter" MouseLeave="CB1_MouseLeave" Source="/ConfigurationWindowsDemo;component/Images/SymbolsOFF1.jpg" MouseRightButtonDown="Cb1on" />

amitkarnik2211 8-Mar-11 5:11am

MouseRightButtonDown is not working

amitkarnik2211 8-Mar-11 5:42am

public void Cb1on(object sender, MouseButtonEventArgs e) { Visibility Image = Collapsed; }

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Tarun.K.S · Accepted Answer · 2011-03-08T00:45:00

Solution 2

XML

<Image MouseRightButtonDown="image1_MouseRightButtonDown" Source="Sunset.jpg" Grid.Row="2" Margin="156,141,0,55" Name="image1" Stretch="Fill" HorizontalAlignment="Left" Width="139.83" />

The handler will disable the image2.

C#

private void image1_MouseRightButtonDown(object sender, MouseButtonEventArgs e)
{
    image2.Visibility = Visibility.Hidden;
}

But how are you going to do vice-versa when the other image gets hidden.

Posted 8-Mar-11 0:45am

Tarun.K.S

Comments

amitkarnik2211 8-Mar-11 7:19am

can we do codes using if & else in such a way that one is visible than other is hidden and vice versa any Idea

Tarun.K.S 8-Mar-11 7:34am

That's puzzling me too because once the Image gets hidden, mouse events won't work and hence you cannot do vice-versa.

amitkarnik2211 8-Mar-11 7:43am

I tried it this way
public void Cb1on_MouseRightButtonDown(object sender, MouseButtonEventArgs e)
{
CBoff1.Visibility = Visibility.Hidden;
}
private void CB1_MouseRightButtonDown(object sender, MouseButtonEventArgs e)
{
CBoff1.Visibility = Visibility.Visible;
}

Tarun.K.S 8-Mar-11 9:26am

Whats CB1?

amitkarnik2211 10-Mar-11 2:02am

There r two Images 1 is CB1 and other is CBoff1 with Red and green colours Respectively on right click I wanted one to be hidden and one to be visible so this happened with above codes and with ur help thanks

Tarun.K.S 10-Mar-11 4:55am

Ohkay glad it helped! Thanks for accepting the answer!