Looping through JSON object based on particular type of Key

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Hi Friends,
I have following Json Object

"lstTimesheet":[{"ConventionID":1,"PhaseID":139,"ActivityID":259,"TaskID":10,"Day1":8.00,"Day2":8.00,"Day3":0.00,"Day4":0.00,"Day5":0.00,"Day6":0.00,"Day7":0.00,"MSPFlag":0,"TimesheetFormat":"MH ","Freeze":0}]}

What I'm trying is, I want only iterate only through keys which has "Day"

I was trying following:

$.each(data.obj.lstTimesheet, function (i, obj) {
                                var txtID = 'txtTime' + (i + 1);
                                var Day = 'Day' + (i + 1);

                                $('#Grid tbody tr').eq(i).each(function () {
                                    $(this).find('td').eq(1).find(txtID).append(obj[Day]);
                                });
                            });

But it is not doing.

Any idea where I'm going wrong??

Thanks in Advance

Posted 11-Nov-13 0:15am

dhage.prashant01

Updated 15-Nov-13 0:10am

v4

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Comments

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 11-Nov-13 6:45am

What it is doing currently? Did you put a debugger and check?

If you can create a jsfiddle, it will be easier for us to check the issue. Just create a fiddle jsfiddle.

2 solutions

Solution 1

Hello prashant,

The listItemsSheet is a JSON Array and in this case contains only a single element. Your loop essentially is going to return the zeroth element which itself is a Json Object. So the loop is going to get called only once, and hence your code fails. The more appropriate way is to re-write this loop as shown below.

JavsScript

$.each(data.obj.lstTimesheet, function (i, obj) {
    if (isJSON(obj)) parseMe(obj);
});

function parseMe(data) {
    var i = 0;

    $.each(obj, function(k, val) {
        if (/^Day/.test(k) {
            var txtID = 'txtTime' + k.substring(;
            $('#Grid tbody tr').eq(i).each(function () {
                $(this).find('td').eq(1).find(txtID).append(val);
            });
            i++;
        }
    });
});

function isJSON(data) {
    var isJson = false
    try {
       var json = JSON.stringify(data);
       isJson = (json != null);
    } catch (ex) {
        console.error('data is not JSON');
    }
    return isJson;
}

Please have a look at a sample demo here[^].

Regards,

Posted 11-Nov-13 0:59am

Prasad Khandekar

Comments

dhage.prashant01 11-Nov-13 7:26am

Thanks Prasad..!!

Prasad Khandekar 11-Nov-13 7:31am

You are welcome Prashant.

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dhage.prashant01 · Accepted Answer · 2013-11-11T01:24:00

Hi friends,
I came up with solution, might it helps others searching for the similar thing

var txtID;
                            var i = 1;
                            for (key in data.obj.lstTimesheet[0]) {

                                if (key.indexOf('Day') != -1) {
                                    var value = data.obj.lstTimesheet[0][key].toFixed(2);
                                    txtID = '#txtTime' + i;

                                    if (key.trim() == 'Day1') 
                                        $('#Grid tbody tr').eq(0).find('td').eq(1).find(txtID).val(value);
                                    else if (key.trim() == 'Day2') 
                                        $('#Grid tbody tr').eq(1).find('td').eq(1).find(txtID).val(value);
                                    else if (key.trim() == 'Day3') 
                                        $('#Grid tbody tr').eq(2).find('td').eq(1).find(txtID).val(value);
                                    else if (key.trim() == 'Day4') 
                                        $('#Grid tbody tr').eq(3).find('td').eq(1).find(txtID).val(value);
                                    else if (key.trim() == 'Day5') 
                                        $('#Grid tbody tr').eq(4).find('td').eq(1).find(txtID).val(value);
                                    else if (key.trim() == 'Day6') 
                                        $('#Grid tbody tr').eq(5).find('td').eq(1).find(txtID).val(value);
                                    else 
                                        $('#Grid tbody tr').eq(6).find('td').eq(1).find(txtID).val(value);

                                    i = i + 1;
                                }
                            }