One To Given Number With Out Using Control Statements And Predefined Methods

Question

1.00/5 (1 vote)

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C

Java

How to print the one to given number.with out using control statements and without using predefined methods

Posted 22-Oct-13 1:00am

Member 10351768

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3 solutions

Solution 1

If you want to print anything - be it on a piece of paper or a screen - you have to use at least one predefined method. The alternative is to write the whole operating system from scratch and that just isn't practical in a little textbox like this one.

In C to a console, it's easy:

C++

int i;
int maxnumber = 10;
for (i = 1; i <= maxnumber; i++)
   {
   printf("%d\n", i);
   }

Other systems or languages may require more work.

"
C#

no,control statements means loops,if statements,break,continue,return statements with out using these things i want the result

"

OK:

C++

printf("%d\n", 1);
printf("%d\n", 2);
printf("%d\n", 3);
printf("%d\n", 4);
printf("%d\n", 5);
printf("%d\n", 6);
printf("%d\n", 7);
printf("%d\n", 8);
printf("%d\n", 9);
printf("%d\n", 10);

You cannot make decisions without control statements of some form: all you can do is write code that runs from the start to the end with no branches, tests or loops - unless you accept an infinite loop. Even the "?" operator is a short form for an "if" control statement.

Posted 22-Oct-13 1:49am

OriginalGriff

Updated 22-Oct-13 2:11am

v2

Comments

Member 10351768 22-Oct-13 8:04am

no,control statements means loops,if statements,break,continue,return statements

with out using these things i want the result

Captain Price 22-Oct-13 8:09am

May I ask why ?

Solution 3

You might want to have a loot at this : http://stackoverflow.com/questions/4568645/printing-1-to-1000-without-loop-or-conditionals[^]

It's neither C nor Java, it's C++. The answer in the loop does not use any loop or condition.

Posted 22-Oct-13 2:20am

Captain Price

Comments

Member 10351768 22-Oct-13 8:25am

i posted one solution just see that one

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Member 10351768 · Accepted Answer · 2013-10-22T02:17:00

Solution 2

C++

class Main{
int i=1;

public static boolean print(int max){
System.out.print(i)
i++;
boolean j=(i<=max)&&print(max);
return j;
}
public static void main(String[] args){
System.out.println("enter the number");
Scanner scanner=new Scanner(System.in);
int max=scanner.nextInt();
print(max);
}

Posted 22-Oct-13 2:17am

Member 10351768

Updated 22-Oct-13 2:27am

v3

Comments

Captain Price 22-Oct-13 8:27am

Wrong answer. This uses many methods.