How to get the time difference in sql

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Hi,
i have one table look like:

Checkin ****** Ckeckout ***** Difference
--------------- --------------- -------------
8/19/2013 08:19 ***** 8/19/2013 10:19
8/19/2013 11:10 ***** 8/19/2013 12:19

In this i want the difference of checkin column and checkout row column in Difference column...

Posted 25-Aug-13 18:03pm

Nawab Ahmad

Updated 25-Aug-13 18:08pm

v3

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3 solutions

Solution 3

You can calculate difference using DATEDIFF function like

DATEDIFF(option,'1997-12-31 23:59:59','1997-12-30')

Posted 25-Aug-13 18:15pm

Member 9714428

Updated 25-Aug-13 18:18pm

v3

Solution 1

http://forums.asp.net/t/1188751.aspx/1[^]

Hope it will help..

Posted 25-Aug-13 18:13pm

Code-Hunt

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ArunRajendra · Accepted Answer · 2013-08-25T18:14:00

Solution 2

Try this.

select DATEDIFF(MI,'8/19/2013 08:19','8/19/2013 10:19')

Posted 25-Aug-13 18:14pm

ArunRajendra

Comments

Nawab Ahmad 26-Aug-13 0:46am

checkin checkout
8/19/2013 14:53 NULL
8/19/2013 16:46 NULL
8/19/2013 08:20 8/19/2013 08:50
8/19/2013 12:40 8/19/2013 13:20
NULL 8/19/2013 13:22
NULL 8/19/2013 14:52
NULL 8/19/2013 18:22
NULL 8/19/2013 16:21
NULL 8/19/2013 16:45
NULL 8/19/2013 16:45
NULL NULL

i am executing one query to insert the value from other table in checkin
INSERT INTO diff(CHECKIN ) SELECT checktime from checkinout where sensorid='1'
working fine
but when i m trying to execute the other query to insert the value in checout

INSERT INTO diff(CHECKout ) SELECT checktime from checkinout where sensorid='2'

it can't replace the null value

it is coming like this..
8/19/2013 14:53 NULL

but i want to be like..
8/19/2013 14:53 8/19/2013 8:50

ArunRajendra 26-Aug-13 1:08am

You need to update the column CHECKout for records created for CHECKIN. Insert will always make a new entry.

Nawab Ahmad 26-Aug-13 1:19am

thank for ur reply..
what i need to modify in this query to makeit work..

INSERT INTO diff(CHECKout ) SELECT checktime from checkinout where sensorid='2'