want a regular expression which will find a string which is enclosed in double quotes and starts with $.

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I want a regular expression which will find a string which is enclosed in double quotes and starts with $.

Example:

input : "$abcd" ("abcd" can any string)
output : abcd

input can be array of string or a string which contains multiple combination of input ("$abcd").

After getting output i want to replace that string with other word.

Please help me on this.

Thank you.

Posted 8-Aug-13 8:24am

Member 10193563

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Manfred Rudolf Bihy 8-Aug-13 14:27pm

So what have you tried and where exactly are you stuck?

Cheers!

Member 10193563 8-Aug-13 15:01pm

I have tried it by find it by using the
int start = indexOf('$')
int end = indexOf('"')
string str = substring(start+1,end-1,(end-start))

but i am not getting expected result.
Actually i am reading xml file into string array by using File.ReadAllLines() method. And i want find all strings which starts with $ enclosed in double quotes. After that i want to reaplce that word with other string.

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Kenneth Haugland · Accepted Answer · 2013-08-08T08:34:00

Solution 1

You havent defined your search very good, so the regex could be defined as this:

C#

string MatchString = "["][$](?<Name>[A-Za-z]+)["]";

You can test out expressions with this tool:
http://www.ultrapico.com/expresso.htm[^]

Posted 8-Aug-13 8:34am

Kenneth Haugland

Updated 8-Aug-13 9:03am

v2

Comments

Member 10193563 8-Aug-13 15:04pm

Actually my question is how to get string a which starts with $ and enclosed in double quotes.
example:
input : "$abcd"
output: abcd

Kenneth Haugland 8-Aug-13 15:05pm

THe capturegroup Name gives the string.

Member 10193563 8-Aug-13 15:18pm

There is some error in regular expression. There is issue of double quotes.

Kenneth Haugland 8-Aug-13 15:33pm

Did you use the capturegroupe as a result? Cos I couldnt find a proble, vould you give an example?

Member 10193563 8-Aug-13 15:44pm

Hey thanks a lot.... I got the solution.... It really helped me...Thank you very much.

Kenneth Haugland 8-Aug-13 15:50pm

Thank you, and you're welcome :-)

Member 10193563 12-Aug-13 4:39am

Hi Kenneth,

I want one more help from you, in the same regular expression i want the a string which will accept a string contains '[]' brackets in it along with the current working.

Example:
1. input : input : "$abcd" ("abcd" can any string)
output : abcd
2. input : "$abcd[]" ("abcd" can any string)
output : abcd[]

First example is working properly but I need second as well in same regular expression.

Thank you in advance..

Member 10193563 12-Aug-13 7:05am

Hey I got the solution.....I have modified the regular expression......

Thank you..

Kenneth Haugland 12-Aug-13 8:07am

ANy character could be found using either [ ] or \, so for the $ sign you can get into trouble becouse the $ is also start of line, so I put this inside [$] to get it, but for any other character you can use \[ to get [ etc.

Member 10193563 12-Aug-13 9:07am

Yes, i tried the same... and I got the solution.
Thank you.

Member 10193563 30-Sep-13 9:16am

Hi Kenneth,

I need one more help. Again i want to customize the regular expression,
Regular Expression : "[\'][$](?[A-Za-z]+)[\']";

in above expression if,
input : ";#SEP;$abcd[]" or "$abcd[]" or ";#SEP;$abcd"
output should be : abcd[]

I want to ignore ";#SEP;" string. Please help me out.

Thanks in advance.

Kenneth Haugland 30-Sep-13 10:12am

You should ask a new question :-)

Member 10193563 30-Sep-13 10:17am

Ok, but this question belongs to the same thread thats why i updated the same thread. shall i raise new question or continue with the same?

Member 10193563 30-Sep-13 10:39am

Shall i raise the new question?

Kenneth Haugland 30-Sep-13 10:43am

I think you should even if its kind of related, as people should be able to search up their problem on the web, and find these answers. So yes :-)

Member 10193563 30-Sep-13 10:52am

Hey i got the solution. I solved it on my own. Thank you very much. and sorry for disturbing you.

Thank you.

Member 10193563 8-Aug-13 15:34pm

It is working now.
Corrected Regular Expression : "[\'][$](?<name>[A-Za-z]+)[\']";
Thanks, it is working.

Here i am getting 'Name' string, but it can contain any string, means any combination of characters. can you make it as a generic. Means i can get any string from it.

Thank you...