User can type Only Numeric valuesin the textbox

Question

1.00/5 (1 vote)

See more:

How can I solve this problem

C#

private void txtTestingNumeric_TextChanged(object sender, EventArgs e)
       {
           if (System.Text.RegularExpressions.Regex.IsMatch("[^0-9]", txtTestingNumeric.Text))
           {
               MessageBox.Show("Please enter only numbers.");
               txtTestingNumeric.Text.Remove(txtTestingNumeric.Text.Length - 1);
           }
       }

Please help me
thanks in advance

Posted 29-Jul-13 21:36pm

Hem Raj Thakur

Updated 29-Jul-13 22:08pm

Ankur^\m/

v2

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Comments

Hem Raj Thakur 30-Jul-13 3:44am

This will create a same error if you press back space on this textbox multitime

Ankur^\m/ 30-Jul-13 4:08am

Edited to add c# tag. Please tag your question properly to get accurate answers.

5 solutions

Solution 3

C#

private void TectBox1_KeyPress(object sender, KeyPressEventArgs e)
       {
           if ((e.KeyChar >= 48 && e.KeyChar <= 57) )
           {
               e.Handled = false;
           }
           else
           {

               e.Handled = true;
           }
       }

Posted 29-Jul-13 21:59pm

jackspero18

Comments

Thomas Daniels 30-Jul-13 4:02am

Reason for my vote of 3: your code is almost correct, but you should also allow a backspace (KeyChar for a backspace is 8)

Solution 5

This Is Best Code.. It will allow you to use only numbers and Space and Backspace

C#

private void txttax1_KeyPress(object sender, KeyPressEventArgs e)
       {
           if ((e.KeyChar >= 48 && e.KeyChar <= 57) || (e.KeyChar == 32) || (e.KeyChar == 8))
           {
               e.Handled = false;
           }
           else
           {

               e.Handled = true;
           }
       }

Posted 29-Jul-13 22:07pm

jackspero18

Updated 29-Jul-13 22:11pm

v2

Solution 6

C#

private void txtTestingNumeric_KeyPress(object sender, EventArgs e)
{
    if (!char.IsControl(e.KeyChar) && !char.IsDigit(e.KeyChar))
    {
        e.Handled = true;
    }
}

Posted 29-Jul-13 22:08pm

berrymaria

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Zafar A khan · Accepted Answer · 2013-07-29T21:59:00

Solution 2

use the keyPress event of textbox like this

C#

private void txtTestingNumeric_KeyPress(object sender, KeyPressEventArgs e)
       {
           int ascii = e.KeyChar;
           if ((ascii >= 48 && ascii <= 57) || ascii == 8 || ascii == 13 || ascii==46)
           {
               e.Handled = false;
           }
           else
           {
               e.Handled = true;
           }
       }

Posted 29-Jul-13 21:59pm

Zafar A khan

Comments

Thomas Daniels 30-Jul-13 4:00am

+5!

Thanks7872 30-Jul-13 4:03am

Why to do this in code while we can check it in definition itself? See my solution.

Thomas Daniels 30-Jul-13 4:04am

Who says that the OP uses ASP.NET? My guess was Windows Forms because MessageBox.Show was used.

Thanks7872 30-Jul-13 4:42am

Your guess was Windows Forms,but my guess is ASP.NET. The question is not tagged properly,so this point doesnt stands. I see no reason for down voting. He is just intended to use numeric textbox and i provided that.

Thomas Daniels 30-Jul-13 4:46am

Rohan Leuva wrote:
I see no reason for down voting
I didn't downvote you.

Hem Raj Thakur · Accepted Answer · 2013-08-29T20:17:00

C#

private void txtamount_KeyDown(object sender, KeyEventArgs e)
      {
          try
          {
              if (e.KeyValue >= 48 && e.KeyValue <= 57 || e.KeyValue == 17|| e.KeyValue == 20 || e.KeyValue == 92 || e.KeyValue == 46 || e.KeyValue == 45 || e.KeyValue == 18 || e.KeyValue == 91 || e.KeyValue == 32 || e.KeyValue == 93 || e.KeyValue == 16 || e.KeyValue == 13 || e.KeyValue == 8 || e.KeyValue == 33 || e.KeyValue == 34 || e.KeyValue == 35 || e.KeyValue == 36 || e.KeyValue == 37 || e.KeyValue == 38 || e.KeyValue == 39 || e.KeyValue == 40 || e.KeyValue == 27 || e.KeyValue == 144 || e.KeyValue == 96 || e.KeyValue == 97 || e.KeyValue == 98 || e.KeyValue == 99 || e.KeyValue == 100 || e.KeyValue == 101 || e.KeyValue == 102 || e.KeyValue == 103 || e.KeyValue == 104 || e.KeyValue == 105 || e.KeyValue == 106 || e.KeyValue == 107 || e.KeyValue == 108 || e.KeyValue == 109 || e.KeyValue == 110 || e.KeyValue == 111 || e.KeyValue == 112 || e.KeyValue == 113 || e.KeyValue == 114 || e.KeyValue == 115 || e.KeyValue == 116 || e.KeyValue == 117 || e.KeyValue == 118 || e.KeyValue == 119 || e.KeyValue == 120 || e.KeyValue == 121 || e.KeyValue == 22 || e.KeyValue == 123 || e.KeyValue == 145 || e.KeyValue == 19)
              {

              }
              else
              {
                  if (e.Alt && e.KeyCode == Keys.N || e.Alt && e.KeyCode == Keys.S || e.Alt && e.KeyCode == Keys.E || e.Alt && e.KeyCode == Keys.C)
                  {

                  }
                  else
                  {
                      MessageBox.Show("Ooops! Only numeric allowed.", "School Charge Master", MessageBoxButtons.OK, MessageBoxIcon.Warning);
                      try
                      {
                          txtamount.Text = "";
                          txtamount.Focus();
                      }
                      catch (Exception)
                      { }
                  }
              }
          }
          catch
          {
          }
      }

this is for (.) allow e.KeyValue == 190

User can type Only Numeric valuesin the textbox

5 solutions

Solution 2

Solution 3

Solution 5

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